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3 years ago

Find an equation of the line having the given slope and containing the given point.

Mathematics

1 answer:

Artemon [7]3 years ago

5 0

Answer:

y + 4 = -3(x - 2)

y + 4 = -3x + 6

y = -3x + 2

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Help me i am so confused

shusha [124]

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6 0

3 years ago

-25 Points-<br> Find the area of the LARGER sector.<br> Leave your answer in terms of pi.

Pavlova-9 [17]

Answer:

33 pi

Step-by-step explanation:

Area of the larger sector = Area of the circle - Area of the smaller sector

Area of the circle = (6)^2 pi = 36 pi

Area of the smaller sector = 1/2 × (6)^2 × theta....,where theta has to be in radians

30° = pi/6

Area of the smaller sector = 1/2 × 36 × pi/6

= 3 pi

Area of the larger sector = 36 pi - 3 pi

Area = 33 pi

3 0

3 years ago

Nayeli light a 4m² space with 12 candles. Citlali lights a 10m² space with 30 of the same type of candles. Whos space is lit bri

Norma-Jean [14]

Answer:

Both spaces have the same amount of brightness per square meter.

Step-by-step explanation:

Nayeli: 12 candles / 4 square meters is the same as 3 candles per square meter.

Citlali: 30 candles / 10 square meters is the same as 3 candles per square meter.

So both Nayeli's and Citlali's spaces have the same amount of brightness per square meter.

5 0

2 years ago

Read 2 more answers

If the point (2/3,y) is on the unit circle, what is y?

LUCKY_DIMON [66]

On the unit circle, the abscise (x) is the cosine and the ordinate (y) = sinus
So y is the sinus

8 0

3 years ago

A computer program has a bug that causes it to fail once in every thousand runs, on average. In an effort to find the bug, indep

Serhud [2]

Answer:

The standard deviation of the number of runs required is 2447.26

Step-by-step explanation:

For each run, there are only two possible outcomes. Either the program fails, or it does not. The probability of the computer failing during a run is independent of other runs. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The standard deviation for the expected number of trials for r sucesses is:

$\sqrt{V(X)} = \sqrt{\frac{r(1-p)}{p^{2}}}$

A computer program has a bug that causes it to fail once in every thousand runs, on average.

This means that $p = \frac{1}{1000} = 0.001$

In an effort to find the bug, independent runs of the program will be made until the program has failed six times. What is the standard deviation of the number of runs required?

This means that r = 6. So

$\sqrt{V(X)} = \sqrt{\frac{6*0.999}{(0.001)^{2}}} = 2447.26$

The standard deviation of the number of runs required is 2447.26

8 0

3 years ago