The question in line 9 is intended to
1 answer:
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Answer:
2 3/4 C
Step-by-step explanation:
Answer:
a₈ = 37
Step-by-step explanation:
The given arithmetic sequence is: 3, 8, 13, 18, 23, . . .
The recursive formula for the sequence is:
Here, represents the
of the sequence.
And, represents the
of the sequence.
'+5' denotes that '5' is added to the term to get the
term. In other words, the difference between two consecutive numbers in the sequence is 5.
Now, we are asked to find a₈ i.e., n =8.
Substituting in the recursive formula we get: a₈ = a₍₈₋ ₁₎ + 5 = a₇ + 5.
So, to determine a₈ we need to know a₇. From the sequence we see that a₅ = 23.
⇒ a₆ = 23 + 5 = 28.
⇒ a₇ = 28 + 5 = 32.
⇒ a₈ = 32 + 5 = 37.
Therefore, the term of the sequence is 37.
Answer:
The answer to the question is
The ratio of the two gas pressures , that is Px to Py = 1/6
Step-by-step explanation:
Let the gases Volumes be V₁ and V₂
Where volume of X = V₁ and
volume of Y = V₂
The volume of Y is half the volume of X
∴ V₂ = × V₁
Let the number of moles be n₁ and n₂ in X and Y respectively
therefore n₂ = 3 × n₁
The pressure of the gas in X is Pₓ and the pressure of the gas in Y is then we have
P₁ × V₁ = n₁ × R × T₁ , and P₂ × V₂ = n₂ × R × T₂
(P₁ × V₁)/(n₁ × T₁) = (P₂ × V₂)/(n₂ × T₂)
but T₁ = T₂
Therefore
(P₁ × V₁)/n₁ = (P₂ × V₂)/n₂. However n₂ = 3 × n₁ and V₂ = × V₁ therefore substituting in the equation we have
(P₁ × V₁)/n₁ = (P₂ × × V₁ )/(3 × n₁) from where
P₁ /P₂ = ( × V₁ × n₁)/(V₁×3 × n₁) =0.5/3 = 1/6
The ratio of = 1/6