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1 year ago

The question in line 9 is intended to

Mathematics

1 answer:

dedylja [7]1 year ago

7 0

The question in line 9 is intended to: provide a typical explanation for the renovations (Option C).

<h3>What is a comprehension passage?</h3>

In a comprehension passage, some questions are given that follow the passage. The questions are to be answered by using the data given in the passage, even if it differs from real-life facts.

Now,

The line 9 is: "Sentimentalism? Hardly. "
The writer here challenges the reader's interpretation after expecting it.
She assumes that many skeptic readers will believe that preserving these historic structures is some sort of sentimental gesture, but she dispels that notion by pointing out that it is actually extremely practical.

Hence, Option C is the most accurate, i.e., The question in line 9 is intended to: provide a typical explanation for the renovations (Option C).

To learn more about comprehension passages, refer to the link:

brainly.com/question/24716030

#SPJ4

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The answer is the option $x+49\°+28\°=180\°$

Step-by-step explanation:

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$28\°+x+49\°=180\°$

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Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

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Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

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At the null hypothesis, we test if the proportion is of at least half, that is:

$H_0: p \geq 0.5$

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

$H_1: p < 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5$

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that $n = 444, X = \frac{202}{444} = 0.455$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

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P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

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