600 + 300 + 150 + . . . is a geometric sequence with a = 600 and r = 1/2
Sn = a(1 - r^n)/(1 - r)
S5 = 600(1 - (1/2)^5)/(1 - 1/2) = 600(1 - 1/32)/(1/2) = 1,200(31/32) = 1,162.5

8 0

2 years ago

help me please, no bots thank you. i’ll give you a brainly if you get it correct :)

Crank

Sorry i wish i knew the answer i’m actually learning that in class but i don’t quite understand it

5 0

1 year ago

Grace's car left four skid marks on the road surface during a highway accident. Two of the skid marks were each 52 feet and two

Mashcka [7]

Answer:

The skid distance to be used is 54 feet.

Step-by-step explanation:

Given:

Four skid marks on the highway.

$52,52,56,56$ in feet.

We have to find the skid distance.

The skid distance that will be used to further calculate the skid speed is actually the mean skid distance.

Mean skid distance (m) :

⇒ $(m)=\frac{Sum\ of \ the\ skid\ marks }{Number\ of\ skid\ marks}$

⇒ $(m) =\frac{52+52+56+56}{4}$

⇒ $(m) =\frac{216}{4}$

⇒ $(m)=54$ feet.

So the skid distance to be used is 54 feet.

7 0

2 years ago