Your answer is B. twice v.
This is because if you were to write out 2v as an expression with its operations, it would be 2 × v, and if you are multiplying v by 2, then the result will be twice the value of v.
I hope this helps!
F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
Answer:
the answers Is c. x=4
Step-by-step explanation:
do substitution 2*4+6=14
and 6*4-10=14
A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5
A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==
The response variable in the study that Ann has done here can be said to be Time spent exercising.
<h3>What is a response variable?</h3>
This is the name that is used to refer to the dependent variable. This is the variable that is of interest in the study. The goal is to see the changes that occurs in the particular variable based on the actions that another variable would have such as the independent variable.
From this we can see that The response variable in the study that Ann has done here can be said to be Time spent exercising.
Read more on response variable here:
brainly.com/question/22046153
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