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mote1985 [20]
3 years ago
10

Penny received an unexpected $5,000.00 gift from a distant relative. She invests it

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

$9,000.00 is her original investment worth in 10 yrs.

5000 x 1.08 ^10 = 10794.6249864

Then subtract -500000 = 5794.62498636

Step-by-step explanation:

Why, because the first year is proved 5000 x 0.08 = 400

= 400 year 1 but cna keep only if stays in investment for 10 years

400 x 10 = 4000 interest on investment

5000+ 4000 = $9,000.00 SI

+ 1,794.62 Interest on interest if applies (this is called CI) and makes $10794.62

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The other form of circle equation is (x-a)2 + (y-b)2 = r2. a and b is the coordinate of the center and r is radius. So the equation is x2+(y-4)2=9. Change it to the general form is x2+y2-8y+7=0. So A=1, B=1, C=0, D=-8 and E=7.
6 0
3 years ago
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Consider U = {x|x is a real number}. A = {x|x ∈ U and x + 2 > 10} B = {x|x ∈ U and 2x > 10} Which statements are true? 5 ∉
-Dominant- [34]

x+2 > 10 solves to x > 8 after we subtract 2 from both sides

So set A is the set of real numbers that are larger than 8. The value 8 itself is not in set A. The same can be said about 5 as well.


Set B is the set of values that are larger than 5 since 2x > 10 turns into x > 5 after dividing both sides by 2. The value x = 5 is not in set B since x > 5 would turn into 5 > 5 which is false. The values x = 6, x = 8, and x = 9 are in set B.


----------------


Summarizing everything, we can say...

5 is not in set A. True

5 is in set B. False

6 is in set A. False

6 is not in set B. False

8 is not in set A. True

8 is in set B. True

9 is in set A. True

9 is not in set B. False


5 0
3 years ago
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Randy wants to use the Distributive Property to rewrite 56-21. Which expression could he use?
stiks02 [169]
B is your answer.
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3 years ago
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last year my math book cost $126,and i was told the price would increase 9% each year. If the cost continues to increase at this
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3 years ago
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Solve the following system of equations 3x+4y=16 and -4x-3y = -19
BigorU [14]
3x + 4y = 16
-4x - 3y = -19

4( 3x + 4y = 16)
3( -4x - 3y = -19)
Distribute
12x + 16y = 64
-12x - 9y = -57
Now subtract both equations
7y = 7
/7 on both sides
y = 1

Substitute y = 1 in one of the equations.
3x + 4y = 16
3x + 4(1) = 16
-4 on both sides
3x = 12
/3 on both sides
x = 4

Answer:
x = 4
y = 1
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3 years ago
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