Answer:
22
Step-by-step explanation:
We can use the order of operations (PEMDAS), to solve this equation.
We must first multiply and divide, and order. This means we divide 12 by 3 and get 4, then multiply that by 2 and get 8. (30-12÷3×2,30-4×2,30-8). Now we just subtract 8 from 30 and get 22 as our answer.

Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer: 34
Step-by-step explanation: 4(7)+6
28+6 = 34
The answer is 2 duh but it also equals window :)