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ELEN [110]
1 year ago
13

The fastest recorded speed for an eastern gray kangaroo is 40 mph. What was the

Mathematics
1 answer:
Ludmilka [50]1 year ago
3 0

The kangaroo's speed in feet per second is 58.67 feet per second

<h3>What was the kangaroo's speed in feet per second?</h3>

The speed is given as:

Speed = 40 mph

Rewrite properly as

Speed = 40 miles per hour

1 mile = 5280 feet

So, we have

Speed = 40 * 5280 feet per hour

Evaluate

Speed = 211200 feet per hour

1 hour = 3600 seconds

So, we have:

Speed = 211200 feet per 3600 seconds

Evaluate the quotient

Speed = 58.67 feet per seconds

Hence, the kangaroo's speed in feet per second is 58.67 feet per seconds

Read more about speed at:

brainly.com/question/4931057

#SPJ1

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A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin
patriot [66]

Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

7 0
3 years ago
Q7. Average of 60 numbers are 55. When 10 more numbers are included, the average of
Nikitich [7]

Answer:

The average of the 10 numbers is 195

Step-by-step explanation:

The average of a set of numbers is the sum of the numbers dividing by their number

  • Average = The sum ÷ The number

∵ The average of 60 numbers is 55

∴ The average = 55

∴ The number = 60

→ Substitute them in the rule above to find the sum of the numbers

∵ 55 = The sum ÷ 60

→ Multiply each side by 60

∴ 3300 = The sum

∴ The sum of the 60 numbers = 3300

∵ 10 more numbers are included

∵ The average of  70 numbers become 75

∴ The average = 75

∴ The number = 70

→ Substitute them in the rule above to find the sum of the numbers

∵ 75 = The sum ÷ 70

→ Multiply each side by 70

∴ 5250 = The sum

∴ The sum of the 70 numbers = 5250

∵ The sum of the 10 numbers that added is the difference between

   the sums of the 60 and 70 numbers

∵ The difference between the sums = 5250 - 3300

∴ The difference between the sums = 1950

→ To find the average of them divide their sum by 10

∵ The average of the 10 numbers = 1950 ÷ 10

∴  The average of the 10 numbers = 195

5 0
3 years ago
2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18
anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0
3 years ago
Holaaaaaaaaaaaaaaaaaaaaaaaaaa
tino4ka555 [31]

Answer:

HIIIIIIIIIIII

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Hi pls help me in math im soo stuck:(((​
Genrish500 [490]
2x = 48, 3x = 72, 4x = 96, 6x = 144


2x + 3x + 4x + 6x = 360
15x = 360
x = 24

2x = 2(24) = 48
3x = 3(24) = 72
4x = 4(24) = 96
6x = 6(24) = 144
8 0
2 years ago
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