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jonny [76]
2 years ago
14

Find cotθ, cosθ, and secθ, where θ is the angle shown in the figure.

Mathematics
1 answer:
Darina [25.2K]2 years ago
5 0

Answer:

\cos( \theta)  =  \frac{5}{8}  \\  {8}^{2}  =  {5}^{2}  +  {opp}^{2}  \\ {opp}^{2}  = 64 - 25 = 39 \\ opp =  \sqrt{39}  \\  \sin(\theta)  =  \frac{\sqrt{39}}{8}  \\  \tan(\theta)  =  \frac{ \sqrt{39} }{5}  \\  \cot(\theta)  =  \frac{1}{\tan(\theta)}  =  \frac{1}{\frac{ \sqrt{39} }{5}}  \\ \cot(\theta)  =  \frac{5}{ \sqrt{39} }  \\  \csc( \theta) =  \frac{1}{\sin(\theta)}  =  \frac{1}{\frac{\sqrt{39}}{8}}   \\ \csc( \theta) = \frac{8}{ \sqrt{39} }  \\  \sec( \theta) =  \frac{1}{\cos( \theta) }  =  \frac{1}{ \frac{5}{8} }  \\ \sec( \theta) =  \frac{8}{5}

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The probability that a student participates in both sports and drama is 0.14.

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If A and B are any two events, then the probability of the joint event (A\cup B) is given by the following formula: P(A\cup B)=P(A)+P(B)-P(A\cap B)

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose S denotes that "a student participates in sports" and D denotes that "a student participates in drama".
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By the above formula, we obtain:

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Therefore, the probability that a student participates in both sports and drama is 0.14.

To learn more about probability, refer: brainly.com/question/24756209

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