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1 year ago

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What is d if

itle="\frac{3d-2}{8} = -d+16\frac{1}{4}" alt="\frac{3d-2}{8} = -d+16\frac{1}{4}" align="absmiddle" class="latex-formula">

1 answer:

Harlamova29_29 [7]1 year ago

8 0

Answer: d=12

Step-by-step explanation:

$\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}$

Multiply both parts of the equation by 8:

$\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\$

Divide both parts of the equation by 11:

$d=12$

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Help me Solve 1/6 ÷ 2/6 please

pochemuha

$\frac{1}{6}$ ÷ $\frac{2}{6}$

First, apply this following rule: $a$ ÷ $\frac{b}{x} = a$ × $\frac{c}{b}$
$\frac{1}{6}$ × $\frac{6}{2}$
Second, apply this following rule: $\frac{a}{b}$ × $\frac{c}{d} = \frac{ac}{bd}$
$\frac{1x6}{6x2}$
Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
$\frac{6}{12}$
Fourth, find the GCF of 6 and 12.
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.
$6$ ÷ $6 = 1$
Sixth, divide the denominator by the GCF.
$12$ ÷ $6 = 2$
Seventh, collect the new numerator and new denominator.
$\frac{1}{2}$

Answer as fraction: $\frac{1}{2}$
Answer as decimal: 0.5

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3 years ago

A rectangles tabletop has a length of 4 3/4 feet and a area of 11 7/8 square feet what is the width of the tabletop

Natalija [7]

Area is length times width. Therefore, width is area divided by length. Convert 11 7/8 to the improper fraction 95/8 and convert 4 3/4 to 19/4. Then, you can fine 95/8 divided by 19/4 by flipping the second fraction and multiplying so that you have 95/8 times 4/19. 4 times 95 is 380 and 8 times 19 is 152. Therefore, the answer is 380/152. This is equivalent to 5/2 or 2.5.

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2 years ago

What is the greatest common factor of 10 and 4?

cluponka [151]

Answer:

Answer: GCF of 4 and 10 is 2.

Step-by-step explanation:

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2 years ago

Read 2 more answers

A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin

Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

$P(\dfrac{X}{Y}) = 60\% = 0.6$

$P(\dfrac{X}{Y'}) = 0.01\% = 0.0001$

$P(Y) = 0.01$

Thus, $P(Y') \ will\ be = 1 - P(Y)$

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

$P(YX) = P(\dfrac{X}{Y}) \ P(Y)$

$P(YX) =0.6 \times 0.01$

$P(YX) =0.006$

The probabilities of not involved in cheating & the evidence are present is:

$P(Y'X) = P(Y') \times P(\dfrac{X}{Y'})$

$P(Y'X) = 0.99 \times 0.0001 \\ \\ P(Y'X) = 0.000099$

(b)

The required probability that the evidence is present is:

P(YX or Y'X) = 0.006 + 0.000099

P(YX or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

$P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}$

$P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}$

$P(\dfrac{Y}{X}) = 0.9838$

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2 years ago

2. The 7th term of an A.P is 27 and the 12th term is 47, what is the sequence?

Vera_Pavlovna [14]

Answer:

<h2>3 + 4(n - 1)</h2>

Step-by-step explanation:

let r be the common differenc of the sequence

Term 12 - Term 7 = (12 - 7)r

then

47 - 27 = 5r

then

20 = 5r

then

r = 4

term 7 = term 1 + (7 - 1)r

then

27 = term 1 + 6r = term 1 + 24

then

Term1 = 27 - 24 = 3

<em><u>therefore </u></em>

the standard explicit formula of the sequence is :

term 1 + (n - 1)r = 3 + 4(n - 1)

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3 years ago