Question

What is d if itle="\frac{3d-2}{8} = -d+16\frac{1}{4}" alt="\frac{3d-2}{8} = -d+16\frac{1}{4}" align="absmiddle" class="latex-formula">

Answer 1

Answer: d=12

Step-by-step explanation:

$\displaystyle\\\frac{3d-2}{8} =-d+16\frac{1}{4} \\\\\frac{3d-2}{8} =-d+\frac{16*4+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{64+1}{4} \\\\\frac{3d-2}{8} =-d+\frac{65}{4}$

Multiply both parts of the equation by 8:

$\displaystyle\\3d-2=(-d+\frac{65}{4} )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132$

Divide both parts of the equation by 11:

$d=12$