To answer this, you will determine what fraction of the original rocks are silver by using the information about the other two colors.
If 2/3 of them area purple, than 1/3 are not.
If 3/4 of the remaining 1/3 is blue, than 3/4 x 1/3 = 3/12 of then are blue.
2/3 are purple, 3/12 of them are blue, the remaining is silver,
1 - 2/3 - 3/12
1 - 8/12 - 3/12 = 1/12
1/12 of the rocks are silver. If 3 are silver, write an equation that needs solved.
1/12r = 3
r = 36 rocks
There were 36 space rocks in total.
Answer:
A. x = 6
Step-by-step explanation:
a^2 + b^2 = c^2
8^2 + b^2 = 10^2
64 + b^2 = 100
b^2 = 100 - 64
b^2 = 36
√b^2 = √36
b = 6
change both the fractions to improper fractions. the area will be 147/4 , and the width will be 9/2 . with both of these you may now divide, (147/4) / (9/2)
remember to use the KCF when dividing fractions.
147 * 2 = 294
4 * 9 = 36
your new fraction will be 294/36 .... which it is also 8 1/6
The height of the ball initially is 54 inches. The common ratio has been provided which is 0.750.
The explicit formular for the geometric sequence is shown as;
The explicit formula is shown as;
54 x (0.750)^9
The rest is simply to solve for the height on the 10th bounce
