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3 years ago

2.9/2.2 X 2.6 find the estimate round to one signifcant figure with each number.

Mathematics

2 answers:

wolverine [178]3 years ago

8 0

Step-by-step explanation:

=2.9/5.72

=0.50

Therefore significant figure = 1

please mark as a brainlest

aivan3 [116]3 years ago

5 0

Answer:

= 2.9/ 5.72

= 0.50

Round off to one significant figure.

= 1

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Ty flipped a coin and counted how many times it landed on heads and how many times it landed on

lesya [120]

<h3>Answer: 13/28</h3>

========================================================

Reason:

The table shows he got 26 heads out of 26+30 = 56 coin flips.

26/56 = (2*13)/(2*28) = 13/28 is the empirical or experimetnal probablity of getting heads.

Side note: 13/28 = 0.4643 = 46.43% approximately which is fairly close to 50%

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2 years ago

Which set of lengths are not the side lengths of a right triangle? (A-28, 45, 53) (B-13, 84, 85) (C-36, 77, 85) (D-16, 61, 65) [

nikklg [1K]

Side lengths 16, 61, and 65 are not part of a right triangle.

A right triangle's sides should follow this formula, C being the largest number:

$a^{2} + b ^{2} = c^{2}$

$16^{2} = 256$

$61^{2} = 3721$

$65^{2} = 4225$

256 + 3721 = 3977

$3977 \neq 4225$

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3 years ago

If you help me I’ll love you forever <3

eimsori [14]

Answer:

translation

Step-by-step explanation:

because a reflection across the x-axis is not right, and neither is across the y-axis. The triangle was also not rotated 90 degrees. It was translated 8 units to the right and 4 units up.

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3 years ago

A triangle has sides with lengths of 43 millimeters, 52 millimeters, and 65 millimeters. Is it a right triangle

Mrrafil [7]

Use pythagora's theorem to test if it is a right triangle

c^2 = a^2 + b^2
65^2 = 52^2 + 43^2
4225 = 2704 + 1849
4225 =/= 4553
therefore it is not a right triangle as it does not comply to pythagora's theorem

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3 years ago

Give the following equations determine if the lines are parallel perpendicular or neither

GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.