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antiseptic1488 [7]
1 year ago
10

drag each tile to the correct box. not all tiles will be used. one solution each is given for four quadratic equations. assuming

that each quadratic equation has two solutions, what is the second solution for each equation? arrowright arrowright arrowright
Mathematics
1 answer:
saw5 [17]1 year ago
4 0

for the equation is, x = -4 - 5i

The  solution will be, x = -4 + 5i

for the equation is, x = 4 + 5i

The  solution will be, x = 4 - 5i

for the equation is, x = 5 - 4i

The  solution will be, x = 5 - 4i

<h3>Quadratic equation defind as:</h3>

Any equation in algebra that can be written in proper format as where x stands for an unknown, where a, b, and c stand for known numbers, and where a 0

<h3>According to the given information:</h3>

If (a + bi) is a complex number and a quadratic equation has one solution,

The second solution to the equation will be the conjugate of the first.

Consequently, the alternative solution will take the form of (a - bi).

for the equation is, x = -4 - 5i

The  solution will be, x = -4 + 5i

for the equation is, x = 4 + 5i

The  solution will be, x = 4 - 5i

for the equation is, x = 5 - 4i

The  solution will be, x = 5 - 4i

To know more about quadratic equation visit:

brainly.com/question/17177510

#SPJ4

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If you have any questions, feel free to comment below.

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