Answer and Explanation:
Make an algorithm of that which include array x of string where Mode of the value of the array means that you have the values such that 1.2,4,2,6,7,8,2 so 2 is the value of set as it appears more than other number similarly when a array of x has been given.First of all initialize a variable then declare it . so for initialization create a variable .Let suppose i create a variable of add and initialize it with 0 and given a it data type integer then
int add= 0; // declaration
int add[]=0; // declaration and initialization in array
class add {
void main(String array[]){
int add[]=0;//declaration and instantiation
int add[] = new int [3];
add[0]=30;//initialization
add[1]=80;
add[2]=20;
output the given array of string
for ( int i = 0 ; i <add.length ;i++)
cout <<add[i];
}
Taking an other example let initialization and declare array of string and print the greater value.For this create a variable with integer data type \
class Test{
void main(String[] array){
//declaration of array
int test[][] = new int [2];
test[0]; new int [2];
test[1]; new int [4];
for initialization of array lets take variable a with data type integer
int a=0;
//taking loop for condition
for (int i=0; i<test.length; i++)
for(int j=0; j<test[i].length; j++)
//if the loops working properly then take increment in the variable a
test[i][j] = a++;
this process repeat until loops got false
for (int i=0; i<test.length; i++)
for(int j=0; j<test[i].length; j++)
cout<<test[i][j]<<"+"<<"";
}
System.out.println();
}
}
