Answer:
x=17
Step-by-step explanation:
3x+5+2x=90
5x=85
x=17
<h3>
Answers:</h3>
- A. T <-> U is a <u>biconditional</u>
- B. (A & B) v (C & D) is a <u>disjunction</u>
- C. R -> ~S is a <u>conditional</u>
- D. P & Q is a <u>conjunction</u>
- E. ~(R v P) is a <u>negation</u>
========================================
Explanations:
- A biconditional is anything in the form A <-> B. This is a compact way of saying (A -> B) & (B -> A). We replace A and B with logical statements.
- Disjunctions are of the basic form A v B. The "v" basically means "or".
- Any conditional is of the form "if... then...". For example, "if it rains, then it gets wet outside" is a conditional. In terms of logic symbols, we write A -> B to mean "if A, then B".
- Conjunctions are whenever we combine two logical statements with an "and" or an ampersand symbol. The basic form is A & B
- Negations are the complete opposite of the original. If the original is P, then the negation is ~P, which is read as "not P".
Answer:
Ok, we have a system of equations:
6*x + 3*y = 6*x*y
2*x + 4*y = 5*x*y
First, we want to isolate one of the variables,
As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:
(6*x + 3*y)/(2*x + 4*y) = 6/5
now we isolate one off the variables:
6*x + 3*y = (6/5)*(2*x + 4*y) = (12/5)*x + (24/5)*y
x*(6 - 12/5) = y*(24/5 - 3)
x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y
Now we can replace it in the first equation:
6*x + 3*y = 6*x*y
6*(0.5*y) + 3*y = 6*(0.5*y)*y
3*y + 3*y = 3*y^2
3*y^2 - 6*y = 0
Now we can find the solutions of that quadratic equation as:

So we have two solutions
y = 0
y = 2.
Suppose that we select the solution y = 0
Then, using one of the equations we can find the value of x:
2*x + 4*0 = 5*x*0
2*x = 0
x = 0
(0, 0) is a solution
if we select the other solution, y = 2.
2*x + 4*2 = 5*x*2
2*x + 8 = 10*x
8 = (10 - 2)*x = 8x
x = 1.
(1, 2) is other solution
1 , 5
5
7
15
i think this is right
Sure, but what do you mean by that?
Its it like a question ot like what