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Vsevolod [243]
1 year ago
14

Tiara is already 6 miles down the road, bicycling at 12 mph, when Dmitri starts down the same road, cycling at 16 mph. According

to the graph, after how many hours do they meet, and how many miles are they from their starting point?
How much time passes before Tiara and Dmitri meet?


When Tiara and Dmitri meet, how far are they from their starting point?
Mathematics
2 answers:
tekilochka [14]1 year ago
8 0
Can you take a picture of the graph please
lutik1710 [3]1 year ago
3 0

Answer:

where is the graph it's needed to answer question

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Pls answer this I need this in 5 mins
zzz [600]

Answer:

x=17

Step-by-step explanation:

3x+5+2x=90

5x=85

x=17

8 0
3 years ago
Read 2 more answers
Match the types of well formed formulas with the expressions. Negation Conjunction Disjunction Conditional Biconditional A. T &l
nikklg [1K]
<h3>Answers:</h3>
  • A. T <-> U  is a <u>biconditional</u>
  • B. (A & B) v (C & D)  is a <u>disjunction</u>
  • C. R -> ~S  is a <u>conditional</u>
  • D. P & Q   is a <u>conjunction</u>
  • E. ~(R v P)  is a <u>negation</u>

========================================

Explanations:

  • A biconditional is anything in the form A <-> B. This is a compact way of saying (A -> B) & (B -> A). We replace A and B with logical statements.
  • Disjunctions are of the basic form A v B. The "v" basically means "or".
  • Any conditional is of the form "if... then...". For example, "if it rains, then it gets wet outside" is a conditional. In terms of logic symbols, we write A -> B to mean "if A, then B".
  • Conjunctions are whenever we combine two logical statements with an "and" or an ampersand symbol. The basic form is A & B
  • Negations are the complete opposite of the original. If the original is P, then the negation is ~P, which is read as "not P".
6 0
3 years ago
Iv)<br>6x+3y=6xy<br>2x + 4y= 5xy​
Margaret [11]

Answer:

Ok, we have a system of equations:

6*x + 3*y = 6*x*y

2*x + 4*y = 5*x*y

First, we want to isolate one of the variables,

As we have almost the same expression (x*y) in the right side of both equations, we can see the quotient between the two equations:

(6*x + 3*y)/(2*x + 4*y) = 6/5

now we isolate one off the variables:

6*x + 3*y = (6/5)*(2*x + 4*y) =  (12/5)*x + (24/5)*y

x*(6 - 12/5) = y*(24/5  - 3)

x = y*(24/5 - 3)/(6 - 12/5) = 0.5*y

Now we can replace it in the first equation:

6*x + 3*y = 6*x*y

6*(0.5*y) + 3*y = 6*(0.5*y)*y

3*y + 3*y = 3*y^2

3*y^2 - 6*y = 0

Now we can find the solutions of that quadratic equation as:

y = \frac{6 +- \sqrt{(-6)^2 - 4*3*0} }{2*3} = \frac{6 +- 6}{6}

So we have two solutions

y = 0

y = 2.

Suppose that we select the solution y = 0

Then, using one of the equations we can find the value of x:

2*x + 4*0 = 5*x*0

2*x = 0

x = 0

(0, 0) is a solution

if we select the other solution, y = 2.

2*x + 4*2 = 5*x*2

2*x + 8 = 10*x

8 = (10 - 2)*x = 8x

x = 1.

(1, 2) is other solution

8 0
3 years ago
Please help me with this
polet [3.4K]
1 , 5
5

7
15

i think this is right
5 0
3 years ago
Anyone inbox me dear friends .​
Vladimir [108]

Sure, but what do you mean by that?

Its it like a question ot like what

4 0
3 years ago
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