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irina [24]
3 years ago
6

A cylinder and a cone have the same volume. The cylinder has radius x and height y. The cone has radius 1/3x. Find the height of

the cone in terms of y.
Mathematics
1 answer:
Temka [501]3 years ago
7 0

Great question! I had this question in Geometry on Edmentum.

Answer: Height of cone = 3y

Step-by-step explanation:

We know that the cylinder and the cone have the same volume. The cylinder has radius x and height y. We will make use of the formulas:

Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

Since the cone has radius 1/3x, we will have to make its height 3 times of y (the height of the cylinder) to make both the cylinder and the cone have the same volume.

So, the height of the cone is equal to 3y.

Hope this helps, and have a wonderful day! :D

Please mark me brainliest! I don't have trouble getting points, but I do when it comes to brainliest.

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Follow the rules to create two number sequences that go to the fifth term each. Rule 1: Multiply by 2 starting at 10. Rule 2: Su
Aleksandr [31]

Answer:

Step-by-step explanation:

Created Sequences

S1: 10 20 40 80 150

s2:24 20

The first term that appears in both sequences is the second term. Both of them equal 20.

I don't think you have to go any further once you get the first term.

Method

S1: Multiply by 2 starting with 10.

10*2 = 20

20*2 = 40

S2: Start at 24 and subtract 4

24 - 4 = 20

20 - 4 = 16

16 - 4 =  12

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2 years ago
A bag contains 3 red balls and 6 blue balls. 2 balls are selected at random. Find the probability of selecting 2 red balls.
Gala2k [10]

Answer: You have 1/3 possibility of grabbing 2 red balls.

Step-by-step explanation:

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3 years ago
Antonio wants to choose a career path in which he would earn a median income of at least $20,000. He wants on-the-job training i
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4 0
3 years ago
Read 2 more answers
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

6 0
3 years ago
Find the length of the mid segment the diagram is not to scale
zepelin [54]
Using the left or right side of triangle, you can conclude that the midsegment will divide the triangle in both midlines of the sides. This means the length of the line would be half of the line below it. The equation would be:

47/4x+2= 94/ 4x+44
4x+44/ 4x+2 = 94/47
4x+ 44 / 4x+2  =2
4x+44  = 2(4x+2)
4x+44 = 8x+4
 4x-8x= 4-44
-4x= -40
x= 10

Then the length of midline would be:
4x+2= 4(10)+2= 42
4 0
3 years ago
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