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castortr0y [4]
3 years ago
8

A 45 degree sector in a circle has an area of 13.75 pi cm squared. what is the area of the circle. use 3.14 for pi

Mathematics
1 answer:
umka21 [38]3 years ago
3 0

Answer: A_c=345.4\ cm^2

Step-by-step explanation:

You need to analize the information given in the exercise.

By definition, there are 360 degrees in a circle.

In this case, you know that  the Central angle in degrees of the  given sector of the  circle is the following:

C=45\°

And the area of that sector is this one:

A_s=13.75\pi\ cm^2

Then, you need to calculate the number of sectors in that circle.

 In order to do it, you have to divide 360 degrees by the central angle of that sector. So, you get:

N\° Sectors=\frac{360\°}{45\°}=8

Knowing that there are 8 sectors in the circle, you need to multiply the area of the sector given in the exercise by 8, in order to calculate the area of the circle.

Therefore, this is (Using \pi =3.14):

A_c=8A_s\\\\A_c=(8)(13.75*3.14)\ cm^2\\\\A_c=345.4\ cm^2

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ratelena [41]

The coordinates of E are (5.75, 0).

<h3>What is midpoint?</h3>

The midpoint is the middle point of a line segment. It is equidistant from both endpoints, and it is the centroid both of the segment and of the endpoints.

Given that, C is the midpoint of AB, D is the midpoint of CB and E is the midpoint of DB.

Formula for coordinates of midpoint,

(x, y) = [(x1+x2)/2, (y1+y2)/2]

Coordinates of C;

(x, y) = (-10+8)/2, (14-2)/2

(x, y) = (-1, 6)

Coordinates of D;

(x, y) = (-1+8)/2, (6-2)/2

(x, y) = (3.5, 2)

Coordinates of E;

(x, y) = (3.5+8)/2, (2-2)/2

(x, y) =  (5.75, 0)

Hence, The coordinates of E are (5.75, 0).

For more references on midpoints, click;

brainly.com/question/28224145

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(comment if spelling is wrong anywhere)

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