<h2>
The mean is $1.60 greater than the median.</h2>
Step-by-step explanation:
Here, the given data is : 896, 925, 880, 963, 914.
Calculating mean of the given data: MEAN = ![\frac{\textrm{Sum of the observations}}{\textrm{Number of observations}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BSum%20of%20the%20observations%7D%7D%7B%5Ctextrm%7BNumber%20of%20observations%7D%7D)
= ![\frac{896 + 925 + 880+ 963+ 914}{5} = \frac{4578}{5} = 915.6](https://tex.z-dn.net/?f=%5Cfrac%7B896%20%2B%20925%20%2B%20%20880%2B%20963%2B%20%20914%7D%7B5%7D%20%20%3D%20%5Cfrac%7B4578%7D%7B5%7D%20%20%3D%20915.6)
Hence, the mean of the given data is $ 915.6
Now, for median, arrange the data in the ascending order.
880, 896, 914 ,925, 963 is the ascending order.
Here,<u> 914 is the MIDDLE TERM</u>.
Hence, MEDIAN of the given data is $ 914.
By comparing mean = $ 915.6 and median = $ 914, we can see that
The mean is $1.60 greater than the median.