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weqwewe [10]
3 years ago
5

Mr. Walker is looking at the fundraiser totals for the last five years.

Mathematics
2 answers:
natka813 [3]3 years ago
7 0

Answer:

B)The mean is $1.60 greater than the median.

Step-by-step explanation:

just took the test

beks73 [17]3 years ago
4 0
<h2>The mean is $1.60 greater than the median.</h2>

Step-by-step explanation:

Here, the given data is :    896, 925, 880, 963, 914.

Calculating mean of the given data:   MEAN = \frac{\textrm{Sum of the observations}}{\textrm{Number of observations}}

= \frac{896 + 925 +  880+ 963+  914}{5}  = \frac{4578}{5}  = 915.6

Hence, the mean of the given data is $ 915.6

Now, for median, arrange the data in the ascending order.

880, 896, 914 ,925,  963  is the ascending order.

Here,<u> 914 is the MIDDLE TERM</u>.

Hence, MEDIAN  of the given data is $ 914.

By comparing mean = $ 915.6 and median = $ 914, we can see that

The mean is $1.60 greater than the median.

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An airline charges the following baggage fees: $25 for the first bag and $35 for the second. Suppose 51% of passengers have no c
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Answer:

The average revenue per passenger is about $13.85

μ = $13.85

The corresponding standard deviation is $14.51

σ = $14.51

The airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.

Expected revenue = $1,662 ± 14.51

Step-by-step explanation:

An airline charges the following baggage fees:

$25 for the first bag and $35 for the second

Suppose 51% of passengers have no checked luggage,

P(0) = 0.51

33% have one piece of checked luggage and 16% have two pieces.

P(1) = 0.33

P(2) = 0.16

a. Build a probability model, compute the average revenue per passenger, and compute the corresponding standard deviation.

The average revenue per passenger is given by

μ = 0×P(0) + 25×P(1) + 35×P(2)

μ = 0×0.51 + 25×0.33 + 35×0.16

μ = 0 + 8.25 + 5.6

μ = $13.85

Therefore, the average revenue per passenger is about $13.85

The corresponding standard deviation is given by

σ = √σ²

Where σ² is the variance and is given by

σ² = (0 - 13.85)²×0.51 + (25 - 13.85)²×0.33 + (35 - 13.85)²×0.16

σ² = 97.83 + 41.03 + 71.57

σ² = 210.43

So,

σ = √210.43

σ = $14.51

Therefore, the corresponding standard deviation is $14.51

b. About how much revenue should the airline expect for a flight of 120 passengers? With what standard deviation?

For 120 passengers,

Expected revenue = 120×$13.85

Expected revenue = $1,662 ± 14.51

Therefore, the airline should expect revenue of $1,662 with a standard deviation of $14.51 for a flight of 120 passengers.

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