A. A group of related objects that do not send out or receive feedback and cannot modify themselves
Explanation:
An open-loop system is a a group of related objects or systems that cannot send out or receive feedback and modify themselves.
- It is a non-feedback system.
- In this system, the output control system has no effect on whatever input that is fed into the system.
- Output and input in such systems are independent of one another.
- The input and output has no control whatever on each other.
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The molarity of H2SO4 is the number of moles in 1 L of solution.
The molarity is 2.0 mol/L
This means that there should be 2 moles in a 1 L solution to make up this molarity.
In this case we need to make up a 5 L solutions with that molarity. Then the amount of moles required are - 2 mol/L x 5 L = 10 mol
Answer:
Step 1 H2 + 2 NO → N2O + H2O (slow)
step 2 N2O + H2 → N2 + H2O (fast)
Explanation:
It is known that the slowest step in a reaction is the rate determining step in a sequence of reactions (reaction mechanism).
We have two important pieces of information in the question to guide our decision making process.
The overall reaction equation, and the rate expression. The two;
2 H2 + 2 NO → N2 + 2 H2O and rate = k[H2][NO]2 all support the answer given above.
Answer:
the equilibrium constant is 1.8 x 10⁻5 and strongly favor the reactants.
Explanation:
the chemical reaction provided for the two equation are the same but different direction i.e a reversible reaction. Assuming, the mass of reactants and product and temperature remain constant.
therefore, the equilibrium constant K, is 1.8 x 10⁻5. this is a very small value of K, thereby strongly favor the backward direction to form reactant.
Number of charge = 5018 C
<h3>Further explanation</h3>
Given
1000 C of charge for x grams of copper
Required
Number of charge
Solution
Faraday's Law :
For 1000 C, W = x grams
For 5x grams :
