Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.
public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}
So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.
A quick explanation:
We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.
The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.
Change the line in word, it basically returns
Answer: Any person or people asking about someone being a hardware or software person displays that they are questioning about the computer knowledge of the person and his/her interest.
The interest can be regarding software tools for programming, designing , etc or hardware device like troubleshooting, assembling the computer parts ,etc.
The person persisting good knowledge about software programming language and software is diverted towards software side .The person who likes to deal with hardware parts of the computer system is hardware-oriented person.
Answer:
I guess this is your answer
development organizations working in developing countries.
Explanation:
If it is wrong srry in advance i just dont know the options
Well, you need to partition your hard drive. Partitioning your hard drive designates usable space on your hdd.
And you need to format your hard drive. Formatting installs a file system on to your hard drive, it allows the operating system to read, write and overall understand the data stored on the disk. Without it, an OS cannot keep track of file locations, nor can it typically identify already used sectors (space) on a hdd.
However, neither of these two concepts are tests.
