B. The number of sharks decreases. Explanation: hope it's help i learned about it and you too
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:

Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:

Speedup gain is 1.81 times.
Answer:
Please kindly check explainations for the code.
Explanation:
lw $t1, Num1
lw $t2, Num2
lw $t3, Num3
blt $t1, $t2, if
beq $t1, $t2, elseif
else:
add $t0, $t3, 5
sw $t0, Result
endif:
#.....other statements after if-elseif-else
if:
sw $t1, Result
b endif
elseif:
ble $t2, $t3, if2
or $t0, $t1, $t3
sw $t0, Result
b endif
if2:
and $t0, $t2, $t3
sw $t0, Result
b endif
Go to attachment for the onscreen code.
Protecting the Power supply
Adding disk Arrays
Install an NLB Cluster