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Tresset [83]
3 years ago
13

Which of the following should be considered when conducting an audience analysis ?

Computers and Technology
2 answers:
lyudmila [28]3 years ago
6 0
1. Think about it
2. Interview the event organizer
3. Interview audiance members
4. Survey your audience members
5. <span>Poll people similar to your audience.
</span>6. <span>Study past event archives.
</span>7. Review current event materials
8. Make observations at the event itself
9. <span>Make observations during your presentation
hope this helps</span>
BartSMP [9]3 years ago
4 0

Answer:

The intended users prior knowledge of the content at hand

Explanation:

Audience analysis means assessing the audience to make sure that the information provided to them is at the appropriate level and that the audience have the prior knowledge of the content at hand.

The audience are the end-user and all communications need to be targeted towards the audience.

Audience analysis looks at: Socio-demographic traits as sex, age, language, religion and where the audience lives.

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Look at the code below. What does it do?
yulyashka [42]

Answer:

3- The code takes in an input, turns it into an integer and then multiplies it by 2 and prints it

Explanation:

Look- First, the code snippet asks for an input (int or float) as "Rawheight".

Aftewards, it converts the input into an integer numeral(if it was a float) and multiplies it by 2.

This processed value is, then, further transferred to the variable "double_height" and is thereafter rendered on the user's virtual screen.

5 0
2 years ago
Let's implement a classic algorithm: binary search on an array. Implement a class named BinarySearcher that provides one static
yKpoI14uk [10]

Answer:

Hope this helped you, and if it did , do consider giving brainliest.

Explanation:

import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}import java.util.ArrayList;

import java.util.List;

//classs named BinarySearcher

public class BinarySearcher {

 

//   main method

  public static void main(String[] args) {

     

//   create a list of Comparable type

     

      List<Comparable> list = new ArrayList<>();

     

//       add elements

     

      list.add(1);

      list.add(2);

      list.add(3);

      list.add(4);

      list.add(5);

      list.add(6);

      list.add(7);

     

//       print list

     

      System.out.println("\nList : "+list);

     

//       test search method

     

      Comparable a = 7;

      System.out.println("\nSearch for 7 : "+search(list,a));

     

      Comparable b = 3;

      System.out.println("\nSearch for 3 : "+search(list,b));

     

      Comparable c = 9;

      System.out.println("\nSearch for 9 : "+search(list,c));

     

      Comparable d = 1;

      System.out.println("\nSearch for 1 : "+search(list,d));

     

      Comparable e = 12;

      System.out.println("\nSearch for 12 : "+search(list,e));

     

      Comparable f = 0;

      System.out.println("\nSearch for 0 : "+search(list,f));

     

  }

 

 

 

//   static method named search takes arguments Comparable list and Comparable parameter

  public static boolean search(List<Comparable> list, Comparable par) {

     

//       if list is empty or parameter is null the throw IllegalArgumentException

     

      if(list.isEmpty() || par == null ) {

         

          throw new IllegalArgumentException();

         

      }

     

//       binary search

     

//       declare variables

     

      int start=0;

     

      int end =list.size()-1;

     

//       using while loop

     

      while(start<=end) {

         

//           mid element

         

          int mid =(start+end)/2;

         

//           if par equal to mid element then return

         

          if(list.get(mid).equals(par) )

          {

              return true ;

             

          }  

         

//           if mid is less than parameter

         

          else if (list.get(mid).compareTo(par) < 0 ) {

                 

              start=mid+1;

          }

         

//           if mid is greater than parameter

         

          else {

              end=mid-1;

          }

      }

     

//       if not found then retuen false

     

      return false;

     

  }

 

 

}

7 0
3 years ago
Which is an appropriate strategy for using a workplace blog?
OLEGan [10]

Answer:

a

Explanation:

8 0
3 years ago
Which is not a characteristic of system testing?
alexandr1967 [171]

Answer:

Characteristics of system testing include;

1. It is the first full assessment of a complete software package.

2. It evaluates the functional, non-functional, and business requirements of a software package.

3. It is similar to black-box testing.

4. It is done by a team of specialized software testers.

5. It helps to ensure the optimal performance of the software after it is deployed.

Explanation:

System testing is a form of software testing that is done to evaluate the full software package before deployment. The testing is done on the basis of some standards and specifications that had been previously established. It is the first testing that is done in a series of software ware testing. This system testing ensures that the functional, business, and non-functional requirements of a software package are met.

It minimizes the problems that are likely to be experienced by a software program that goes unchecked. One such problem is troubleshooting. It is a very important test that should be performed on any developed software.

3 0
3 years ago
Choose the word that best completes this sentence. OSHA requires employers to supply any necessary _________.
PSYCHO15rus [73]
OSHA requires employees to provide any necessary ppe (personal protective equipment) such as gloves or steel toe capped boots 
4 0
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