1. 3 times the light voltage, ie., 3*0.5 = 1.5V
2. Total R = 3*25 = 75Ω, V=1.5V, I = V/R = 1.5/75 = 20 mA
3. A 1.5V battery (e.g., an AA battery) with a charge of at least 20mAh. AA batteries should be able to handle this easily.
The answer is yes hope this helps did before
Answer:
Python code is given below
Explanation:
# create an empty array
arr = []
# loop 5 times
for i in range( 0 , 5 ):
x = float(input('Enter a number : '))
# add x to arr
arr.append( x )
sum = 0
# find the sum of all elements in arr
for x in arr:
sum += x
# calculate average
average = sum / len(arr)
print('\n%15s %15s\n' %('Original Value' , 'Interest Value'))
for Original_value in arr:
# calculate interesr value
Interest_Value = Original_value * 0.2
print('%10f %15f' %( Original_value , Interest_Value ))
print('\nTotal :', sum)
print('Average :', average)
print('Maximum :', max(arr))
print('Miniimum :', min(arr))
