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erma4kov [3.2K]
1 year ago
5

Don’t mind the Answer D I circle can someone explain the answer to me 25 point if no explanation and answer I flagged

Mathematics
1 answer:
Kruka [31]1 year ago
4 0

Answer:

 (A) 49

Explanation:

Given that the fractions are in their simplest form. So below the denominator cannot be a multiple of 3, 4, 5.

Breakdown:

Looking at option A (49), it is not a multiple of 3, 4, 5. So k can be 49.

Option B (50) is a multiple of 5. An even number like 4 so can be simplified.

Option C (51) is a multiple of 3 so can be simplified more. 3/51 = 1/17.

Option D (52) is an even number like 4 so can be simplified. 4/52 = 1/13.

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Two number cubes were rolled 10 times, and the sum of each roll was recorded in the table.
KengaRu [80]

Answer:

shuglot big math explain hoho mamam

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ME... ANYONE.... i am begging you. i will mark brainiest, whatever you want. please help...
Mice21 [21]

Answer:

<h2>5m - 6 = 19</h2>

Step-by-step explanation:

<h3>We are given:</h3>

Monday x 2 = Tuesday

Tuesday - 6 = Wednesday

Lets say

Monday = m

Tuesday = t

Wednesday = w

m = m

2m = t

2m - 6 = w

Combine like terms: 5m - 6 = 19

Add 6 to both sides

5m = 25

Divide both sides by 5

m = 5

Plug it in the equations.

<em>Monday = 5</em>

<em>Tuesday =  10</em>

<em>Wednesday = 4</em>

4 0
3 years ago
Read 2 more answers
A purse contains a collection of quarters, dimes, nickels, and pennies. The average value of the coins in the purse is 17 cents.
bulgar [2K]

Answer:

There are total of 17 coins in the purse

Step-by-step explanation:

Let x represent the no of coins in the purse

Let y represent the total amount

 y/x = 0.17

y = 0.17*x............................(i)

y-0.01 / x-1 = 0.18

y - 0.01 = 0.18x -0.18........(ii)

We substitute y = 0.17 x into the second equation:

0.17x - 0.01 = 0.18x - 0.18

0.17 = 0.01x

x = 17

Hence, there are total of 17 coins in the purse

7 0
3 years ago
This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the ex
azamat

Answer:

Maximum at points (8,0),(-8,0).Minimum at points (0,8), (0,-8).

Step-by-step explanation:

There are multiple ways of using lagrange multipliers. Most of them are equivalent.

Consider the function F(x,y) = x^2-y^2-\lambda(x^2+y^2-64). We want the following \frac{\partial F}{\partial x} = \frac{\partial F}{\partial y} = \frac{\partial F}{\partial \lambda} = 0.

Then, we have

\frac{\partial F}{\partial x} = 2x-2x\lambda= 2x(1-\lambda)=0

\frac{\partial F}{\partial y} = -2y-2y\lambda = -2y(1+\lambda)=0

\frac{\partial F}{\partial \lambda} = x^2+y^2-64=0

From the first two equations, we can see that if \lambda =1 then necessarily y=0. IN that case, from the third equation (which is the restriction) gives us that x=\pm 8.

On the other hand, if \lambda=-1 then necessarily x=0. Again, using the restriction this gives us that y=\pm 8.

if we evaluate the original function in this points, we have that f(0,\pm 8) = -64, f(\pm 8,0)=64. Then, we have Maximum at points (8,0),(-8,0) and Minimum at points (0,8), (0,-8).

3 0
3 years ago
Select the equation of the line that passes through the point (3, −1) and is parallel to the line on the graph.
alexandr1967 [171]
I need more information for it to be solved
8 0
3 years ago
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