Question

Please see the question and solve plz​

Answer 1

Answer:

Step-by-step explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

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sin²β + cos²β = 1  

$\frac{sin^2\beta }{cos^2\beta }$ + $\frac{cos^2\beta }{cos^2\beta }$ = $\frac{1}{cos^2\beta }$ ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

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1 + tan²β = $\frac{1}{cos^2 \beta }$

L.H. = sin²β ( $\frac{1}{cos^2 \beta }$ ) = tan²β

R.H. = tan²β