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Lorico [155]
3 years ago
7

Please see the question and solve plz​

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

Step-by-step explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

~~~~~~~~~~~~~~~~

<u><em>sin²β + cos²β = 1  </em></u>

<u><em /></u>\frac{sin^2\beta }{cos^2\beta } + \frac{cos^2\beta }{cos^2\beta } = \frac{1}{cos^2\beta } ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

~~~~~~~~~~~~~~

1 + tan²β = \frac{1}{cos^2 \beta }

L.H. = sin²β ( \frac{1}{cos^2 \beta } ) = tan²β

R.H. = tan²β

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