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Lorico [155]
3 years ago
7

Please see the question and solve plz​

Mathematics
1 answer:
Korolek [52]3 years ago
7 0

Answer:

Step-by-step explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

~~~~~~~~~~~~~~~~

<u><em>sin²β + cos²β = 1  </em></u>

<u><em /></u>\frac{sin^2\beta }{cos^2\beta } + \frac{cos^2\beta }{cos^2\beta } = \frac{1}{cos^2\beta } ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

~~~~~~~~~~~~~~

1 + tan²β = \frac{1}{cos^2 \beta }

L.H. = sin²β ( \frac{1}{cos^2 \beta } ) = tan²β

R.H. = tan²β

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Answer:

Length = 8 inch , Width = \frac{3}{2} , This equation models the situation

Step-by-step explanation:

Given as ;

The Area of Rectangle is 12 inches²

The Length of Rectangle is 5 inches longer than twice the width

Let The Length = L inches

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According to question ,

L = 5 + (2 × w )

∵ The Area of Rectangle = Length × width

Or, 12  inches²  = [ 5 + (2 × w ) ] ×  w

Or,  12  inches² = 5 w +2 w²

Or,  2 w² + 5 w  - 12 = 0

Or,   2 w² + 8 w  -3 w - 12 = 0

Or,  2 w (w +4) - 3 (w + 4) = 0

I.e (w + 4) ( 2 w - 3) = 0

So ,  w = -4 , and w = \frac{3}{2}

∴  Length = 5 + (2 × w ) =

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so ,  L = 5 + 3 = 8

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3 0
3 years ago
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Check the picture below.

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Step-by-step explanation:

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