All categories

3 years ago

Choose all that apply. Algebraic terms are separated by ______. = - x ÷ +

Mathematics

2 answers:

weeeeeb [17]3 years ago

8 0

I would say all of them except for the equal sign

ipn [44]3 years ago

5 0

I believe the correct answer to this question is - & +. I apologize in advance if the answer I provided is incorrect. -Copelynn.

You might be interested in

Find the formula for the area of the shaded region in the figure.<br> x² = 4py<br> ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$

$A=\frac{8}{3} \sqrt{p h} \cdot h$

In conclusion, the equation for the Area is

$A=\frac{8}{3} \sqrt{p h} \cdot h$

Read more about Area

brainly.com/question/27683633

#SPJ1

5 0

2 years ago

I really need this one answered, I just can’t figure it out.

Katena32 [7]

25.2 divided by 4.2 =6

4 0

3 years ago

I need heelp<br> (-6)-(+8)=

zhuklara [117]

Answer:

I believe its 2 so sorry if im wrong

Step-by-step explanation:

4 0

3 years ago

Inverse of f(x)=3x-4

aniked [119]

Answer:

$\large\boxed{f^{-1}(x)=\dfrac{x+4}{3}=\dfrac{1}{3}x+\dfrac{4}{3}}$

Step-by-step explanation:

$f(x)=3x-4\to y=3x-4\\\\\text{exchange x to y and vice versa}\\\\x=3y-4\\\\\text{solve for y}\\\\3y-4=x\qquad\text{add 4 to both sides}\\\\3y=x+4\qquad\text{divide both sides by 3}\\\\y=\dfrac{x+4}{3}$

8 0

3 years ago

Find all solutions in the interval (0,2pi) you should get kpi and pi/4 but how do you get there

Ket [755]

Add sin(x) to both sides

tan(x)sin(x)=sin(x)

Divide sin(x) from both sides

tan(x)=1

now you just have to figure out where tan(x)=1. you can figure this out from there by looking at the unit circle.

4 0

3 years ago