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wolverine [178]
3 years ago
7

George and carmen went on a bicycle trip. they took a bus to their starting piont, and then biked the rest. they traveled 275 ki

lometers in totals, and they biked 55 kilometers more than they were bussed.
x=kilometers travel by bike and y= kilometers
find how many kilometers they traveled by bike
Mathematics
1 answer:
rodikova [14]3 years ago
5 0
We need to do a system of equations here.

x + y = 275 (if you travel <em>x</em> km by bike and <em>y </em>km by bus, then you travel 275 km as given in the problem)
y = x + 55 (the problem stated that they were bussed (y) the amount they biked plus 55 more km (x + 55))

The second equation is already solved for y. So, we can plug it in to the first equation.

x + (x + 55) = 275
2x + 55 = 275 [combine x terms]
2x = 220 [subtract 55 from both sides]
x = 110 [divide by 2 to isolate x and solve for it]

Now we know that x is 110, the distance they traveled by bike.
And that's what we needed to answer the problem!
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What is 3/4 to the power of 4 as a fraction?
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81 / 256

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3. A soccer team played 160 games and won 65 percent of them. How many games did the team win?
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Answer:

b.) 104

Step-by-step explanation:

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x/y = p/100

where x is the fraction, y is the total, and p is the percent

This means:

x = number of games the team won

y = total number of games

p = percent the number of teams won

Let's plug these values into the equation:

x/y = p/100

x/160 = 65/100

Solve by cross-multiplying:

x/160 = 65/100

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3 years ago
How do I find each measure? Please I need answers ASAP it's due at 1:50
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Answer:

Angle CAD is 44 degrees

Angle ACD is 44 degrees

Angle ACB is 136 degrees

Angle ABC is 22 degrees

Explanation:

29. Triangle ADC is an isosceles triangle because it has two equal sides.

If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.

Let x be angle CAD.

Let's go ahead x;

\begin{gathered} 92+x+x=180\text{ (sum of angles in a triangle)} \\ 92+2x=180 \\ 2x=180-92 \\ 2x=88 \\ x=\frac{88}{2} \\ \therefore x=44^{\circ} \end{gathered}

Therefore, measure of angle CAD is 44 degrees.

30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)

31. Let angle ACB be y,

Let's go ahead and find measure of angle ACB;

\begin{gathered} 44+y=180\text{     (angles on a straight line)} \\ y=180-44 \\ \therefore y=136^{\circ} \end{gathered}

So measure of angle ACB is 136 degrees.

32. Let angle ABC be z.

Triangle ACB is also an isosceles triangle so the base angles are the same.

Let's go ahead and find z;

\begin{gathered} 136+z+z=180_{}\text{    (sum of angles in a triangle)} \\ 138+2z=180 \\ 2z=180-136 \\ 2z=44 \\ z=\frac{44}{2} \\ \therefore z=22^{\circ} \end{gathered}

So measure of angle ABC is 22 degrees.

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