Question

A giant armadillo moving north word with a constant acceleration covers the distance between two points 60 m apart and six seconds its velocity as it passes the second point is 15 m/s

Answer 1

The acceleration is a = 1.7 m/s^2

$v_{0}$The rate at which the velocity of an item in motion changes is known as acceleration.

The sum of all the forces operating on an item, as specified by Newton's second law of motion, produces this value.

We need to know the initial and final velocities as well as the amount of time that has passed in order to calculate acceleration.

We must determine the initial velocity based on the supplied numbers. Some kinematic equations are utilized.

We do as follows:

$x=v_{0}t + \frac{at^{2} }{2}$

x =  60m

t=6 sec

60 = v0(6) + a(6)^2/2

60 = 6v0 + 18a    {equation 1}

$v_{f}=v_{0} + at$

$v_{f}$= 15 m/s

15 = v0 + a(6)

15 = v0 + 6a    {equation 2}

Solving for $v_{0}$ and a,

$v_{0}$ = 5 m/s

a = 1.7 m/s^2

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Answer 2

The acceleration is a = 1.7 m/s²

The rate at which the velocity of an item in motion changes is known as acceleration.

The sum of all the forces operating on an item, as specified by Newton's second law of motion, produces this value.

We need to know the initial and final velocities as well as the amount of time that has passed in order to calculate acceleration.

We must determine the initial velocity based on the supplied numbers. Some kinematic equations are utilized.

Evaluating the problem:

x=$v_{0} t +\frac{at^{2} }{2}$

x =  60m

t=6 sec

60 =$v_{0} 6 + a6^{2} /2$

60 = 6$v_{0}$ + 18a    {equation 1}

$v_{f} = v_{0} +at$

$v_{f}$= 15 m/s

15 = $v_{0}$ + a(6)

15 = $v_{0}$ + 6a    {equation 2}

Solving for  and a,

$v_{0}$ = 5 m/s

a = 1.7 m/s^2

What is Newton's second law ?

Newton's second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

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