Question

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Answer 1

${ \qquad\qquad\huge\underline{{\sf Answer}}}$

Here we go ~

$\qquad \sf \dashrightarrow \: \cfrac{9 {}^{(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} }$

$\qquad \sf \dashrightarrow \: \cfrac{3{}^{2(x + 1)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} }$

$\qquad \sf \dashrightarrow \: \cfrac{3{}^{(2x + 2)} - 3 {}^{2x} }{4 \times 3 {}^{(2x - 1)} }$

here :

• ${ \sf {3}^{(2x+2)}=({3}^{2x - 1})\sdot (3³)}$

• ${ \sf {3}^{(2x)}=({3}^{(2x - 1)})\sdot (3¹)}$

$\qquad \sf \dashrightarrow \: \cfrac{3{}^{(2x - 1)}(3 {}^{3} - 3 {}^{1}) }{4 \times 3 {}^{(2x - 1)} }$

[ taking ${ \sf {3}^{(2x - 1)} }$common here ]

$\qquad \sf \dashrightarrow \: \cfrac{27 {}^{} - 3 {}^{}}{4 }$

$\qquad \sf \dashrightarrow \: \cfrac{24{}^{} {}^{}}{4 }$

$\qquad \sf \dashrightarrow \: 6$

Answer 2

Answer is 6 ................