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Misha Larkins [42]
3 years ago
15

Julissa is running a 10-kilometer race at a constant pace. After running for 18 minutes, she completes 2 kilometers. After runni

ng for 54 minutes, she completes 6 kilometers. Her trainer writes an equation letting t, the time in minutes, represent the independent variable and k, the number of kilometers, represent the dependent variable. Write the equation.
Mathematics
1 answer:
vodomira [7]3 years ago
6 0
First, we need her speed as it will serve as the slope of the equation.
Distance = 2 km
time = 18 min
Speed = 1/9 km/min
k = (1/9)t
Where k is the distance in km and t is the time in minutes.
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Answer:

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What's 7 625/1000 as a decimal fraction
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7.625

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A source of laser light sends rays AB and AC toward two opposite walls of a hall. The light rays strike the walls at points B an
Nataly [62]

Answer:

The distance between the walls is 70 m.

Step-by-step explanation:

Given: A source of laser light is at point A on the ground between two parallel walls BE and CD . The walls are perpendicular to the ground that is

BE ⊥ ED and CD ⊥ ED

AB is a ray of light which strikes the wall on the left at point B which is 30 meters above the ground. that is BE = 30 m

AC is a ray of light which strikes the wall on the right at point C. The length of AC = 80 meters.

The ray AB makes an angle of 45 degrees with the ground that is m∠BAE = 45°

The ray AC makes an angle of 60 degrees with the ground that is m∠CAD = 60°

As shown is figure attached below.

WE have to find the distance between the walls that is Length of ED

Length of ED = EA + AD

Consider the Δ AEB,

Using trigonometric ratio,

\tan\theta=\frac{perpendicular}{base}

Here \theta=45^{\circ} , perpendicular = 30 m  and base we can find.

thus,

\tan 45^{\circ}=\frac{30}{EA}

We know \tan 45^{\circ}=1

thus, EA =  30 m

Consider the Δ AEB,

Using trigonometric ratio,

\cos\theta=\frac{base}{hypotenuse}

Here \theta=60^{\circ} , hypotenuse = 80 m  and base we can find.

thus, \cos 60^{\circ}=\frac{base}{80}

We know, \cos 60^{\circ}=\frac{1}{2}

thus, Base = 40 m

AD = 40 m

Thus, the distance between the walls that is the length of ED = 30 + 40 = 70 m

4 0
3 years ago
Can someone check this out to see if I have this correct? If not can you help me out please? Thank you! The answers are on 2nd p
nataly862011 [7]

Answer:

Answer 1; Angles forming a linear sum to 180°

Answer 2; Substitution

Answer 3; Definition of perpendicular lines

Step-by-step explanation:

The two column proof is presented as follows;

Statement  {}                               Reason

1. ∠SWT ≅ ∠TWU {}                    Given

2. m∠SWT + m∠TWU = 180°  {}  Angles forming a linear sum to 180°

3. m∠SWT + m∠SWT = 180° {}    Substitution

4. m∠SWT = 90°  {}                      Algebra

5. \underset{TV}{\leftrightarrow }⊥ \underset{SU}{\leftrightarrow } {}                                  Definition of perpendicular lines

Perpendicular lines are defined as lines that are at right angles (90°) to each other, therefore given that the angle formed by the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } m∠SWT = 90°, therefore, the lines \underset{TV}{\leftrightarrow } and \underset{SU}{\leftrightarrow } are perpendicular to each other.

3 0
3 years ago
Help please if you can
r-ruslan [8.4K]

Answer:

i cant

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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