Ask question

Ask question

All categories

2 years ago

13

Choose the numbers that are irrational

2 answers:

JulijaS [17]2 years ago

4 0

Answer:

square root 2, pi, 1/3 and 2/7

Korvikt [17]2 years ago

3 0

Only the square root of 2 and pie are irrational. All the others are rational. I made sure of it. And double checked too.

Hope this helps. Have a good day. :)

You might be interested in

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Question 9 of 10

Aleks04 [339]

Answer:

A is the answer

// x = -2(y + 3)2-1

4 0

2 years ago

Need help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!

il63 [147K]

Answer:

d

Step-by-step explanation:

ㅎㅊㄹㅇ효율ㅗㅇㅗㄴㅎㅊㅗ어ㅐ더랴ㅜㄷ훨씬ㅓ로랴류ㅑ류래ㅗㅎ7어ㅗㄹ6휴러ㅓ훠래라7하래러ㅐㅜ여ㅜㅏ

5 0

3 years ago

Please someone help me I will mark you has brainiest

Anna35 [415]

Answer:

i angle EFB

ii BFC and AFC

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

CAN YOU HELP ME PLEASE

mamaluj [8]

Answer:

A

Step-by-step explanation:

7 0

3 years ago