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MakcuM [25]
3 years ago
8

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics
1 answer:
Yuri [45]3 years ago
8 0

Answer:

B. 2

Step-by-step explanation:

she has 2/3 of it done in an 1/3 of an then in an hour 6/3 will be done and 6/3 simplified is 2

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marco and suzi each mulyiplied 0.721 X 100 Marco got 7.21 for his product suiz got 72.1 for her product which student multiplied
Marianna [84]
Size got it right because it’s multiplied by 100
5 0
3 years ago
Factor each expression.<br><br> (9) 5a - 25<br><br> (10) 28 - 7x<br><br> (11) 12z + 28 - 7z - 3
Nimfa-mama [501]

Answer:

Step-by-step explanation:

Look for the GCF and then divide every term by the GCF to see what remains

(9) 5a - 25  ( GCF is 5 so take out 5 and divide every term by 5)

     5(a-5)

(10) 28 - 7x     ( GCF is 7 so take out 7 and divide every term by 7)

     7(4-x)

(11) 12z + 28 - 7z - 3=  (combine terms) =

       5x+25( GCF is 5 so take out 5 and divide every term by 5)

        5(x+5)

6 0
3 years ago
Question 6 of 10 The triangles shown below may not be congruent. 1) 25° 55° 100° 100° 66° 25° O A. True O B. False​
Blizzard [7]

Answer:

True, they may not be congruent

Step-by-step explanation:

A figure cannot be determined as congruent from three angles alone. In order  for two shapes to be congruent, all corresponding parts must be congruent. This means all the sides and angles of the two shapes must be the same in order for the two shapes to be congruent. If we know all the angles are the same, the sides could still be different lengths, so this does not prove congruency.

5 0
3 years ago
HELP PLEASE
kifflom [539]

Answer:

2nd choice

Step-by-step explanation:

to find the inital peanuts, we multiply 32 ounces by 3/10 or 0.3. then we add x which are peanuts as well. that makes 0.3 x 32 + x. this is our total peanuts. to find the percantage, we find the whole mixture which is now 32 + x, divide peanuts by the whole mixture and multiply by 100.

5 0
3 years ago
Read 2 more answers
Here are the endpoints of the segments BC, FG, and JK.<br> B, −67
yulyashka [42]

~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}

F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}

JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill

4 0
2 years ago
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