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Fynjy0 [20]
1 year ago
10

independent variable. what is the independent variable? what are you deliberately choosing or changing?

Mathematics
1 answer:
liq [111]1 year ago
8 0

The independent variable is the factor that you purposely change or control in order to see what effect it has. The variable that responds to the change in the independent variable is called the dependent variable. It depends on the independent variable. The independent variable is graphed on the x-axis.

To identify dependent studies variables, search for objects in your studies query or speculation that sees the result, effect, or outcome of changing the independent variable. The basic rule is to search for what reasons for reactions and what receives the results.

The statistical courting between variables is referred to as their correlation. A correlation might be high-quality, which means each variable circulates in the same direction, or bad, meaning that once one variable's price will increase, the opposite variables' values decrease.

Making sure that certain research variables are managed will increase the reliability and validity of the test, by ensuring that other causal consequences are removed. This safeguard makes it simpler for other researchers to repeat the experiment and comprehensively test the results.

Learn more about variables here brainly.com/question/2804470

#SPJ4

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Identify the domain, range, and codomain in each graph. Then use the codomain and range to determine whether the
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3 years ago
The diagram shows a sector of a circle radius 10cm
Yuki888 [10]

Answer:

\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}

Step-by-step explanation:

\text{Perimeter of the sector = Radius + arc length + radius}

\text{Radius = 10 cm}

\text{Perimeter of the sector = 10 + arc length + 10  }

 \text{Perimeter of the sector = 20 + arc length  }

\text{arc length   = (sector angle/ 360 ) * perimeter of the circle}

\text{Perimeter of a circle }=2\pi r

\text{sector angle} = 135

\text{arc length}   =  (135/ 360 ) * 2\pi (10)

= (3/8) 20\pi

= 15\pi /2

\text{Using  }\pi =3.14

= 15 * 3.14 /2

= 23.55

\text{Perimeter of the sector = 20  + 23.55}

= 43.55

= 43.6  cm

\text{perimeter of the sector  = 43.6  cm }

8 0
2 years ago
1/2×1/3×1/4 need to show work
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1x1x1=1
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Rounding I Got 52.7.
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