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scoundrel [369]
3 years ago
5

12.

Mathematics
1 answer:
UkoKoshka [18]3 years ago
8 0

Answer:

C. y = 3/4x – 12

Step-by-step explanation:

y = 3/4x + b

-18 = 3/4(-8) + b

-18 = -6 + b

-12 = b

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Aliun [14]

Answer:

x⁵/³y

Step-by-step explanation:

x⁵/³y is equivalent to ³✓x⁵y.

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3 years ago
Select all the correct statements
coldgirl [10]
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2 years ago
The locations:
GREYUIT [131]

The quadrilateral is a trapezoid and the area of the quadrilateral is 85.04 square units

<h3>How to determine the quadrilateral?</h3>

The vertices are given as:

A:(-2, 3) B:(4, -6) C:(10, 2) D:(6, 8)

Next, we plot the vertices (see attachment)

From the attached graph, we can see that the quadrilateral is a trapezoid

<h3>How to determine the area?</h3>

From the plot, we have the following features:

Height: AD

Parallel sides: CD and AB

Calculate the lengths using:

d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}

So, we have:

AD = \sqrt{(-2 -6)^2 + (3 -8)^2}

AD = \sqrt{89}

CD = \sqrt{(10 -6)^2 + (2 -8)^2}

CD = \sqrt{52}

AB = \sqrt{(-2 -4)^2 + (3 +6)^2}

AB = \sqrt{117}

The area is then calculated as:

Area = 0.5 * (CD + AB) * AD

This gives

Area = 0.5 * (√52 + √117) * √89

Evaluate

Area = 85.04

Hence, the area of the quadrilateral is 85.04 square units

Read more about areas at:

brainly.com/question/24487155

#SPJ1

7 0
1 year ago
If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?
Lostsunrise [7]
Since \mathrm M_Y(t)=e^{6(e^t-1}, we know that Y follows a Poisson distribution with parameter \lambda=6.

Now assuming \mu,\sigma denote the mean and standard deviation of Y, respectively, then we know right away that \mu=6 and \sigma=\sqrt6.

So,

\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028
6 0
3 years ago
Jan spent 3 3/4 hours doing homework last week. She spent
olchik [2.2K]

Answer:

6/4

Step-by-step explanation:

5 0
2 years ago
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