Question

I have attached the problem in a picture below!​

Answer 1

Answer:

A. The solution set is x = 5 or -7

Step-by-step explanation:

$\sqrt[4]{ {x}^{2} + 2x } = \sqrt[4]{35} \\ {({x}^{2} + 2x) }^{ \frac{1}{4} } = {(35)}^{ \frac{1}{4} } \\ {x}^{ \frac{1}{2} } + {2x}^{ \frac{1}{4} } = {35}^{ \frac{1}{4} } \\ {x}^{2} + 2x = 35 \\ {x}^{2} + 2x - 35 = 0 \\ (x - 5)(x + 7) = 0 \\ x = 5 \: or \: - 7$

Therefore, the answer is A. as the solution is x = 5 or -7