coordinate of B= (2+3,0) = (5,0)
by pythagoras' theorem,
height of triangle^2 + half length of AB^2 = AC^2
height of triangle^2 = 3^2-1.5^2
height of triangle ^2= 6.75
height of triangle= √6.75
coordinates of C= (1.5,√6.75)
Answer:
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Step-by-step explanation:
Y=2x+5
sub 2x+5 for y in other equaiton
10x+3(2x+5)=19
distribute
10x+6x+15=19
minus 15 from both sides
16x=4
divide both sides by 16
x=1/4
sub back
y=2x+5
y=2(1/4)+5
y=1/2+5
y=5.5=11/2
solution is (1/4,11/2) or in decimal, (0.25,5.5)
Y = mx + b. Use this equation for most linear functions. Enter the information that is given to you.

Multiply the -3 and 4 to get 12.

Now divide the -12 from both sides.

-12 cancels out on the right side and your left with

Now re-enter the info back into the formula.

Then you've got your formula