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Mila [183]
2 years ago
9

How many 3 digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is re

peated?.
Mathematics
1 answer:
creativ13 [48]2 years ago
3 0

Number of 3 digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated is 20

A permutation is an act of arranging the objects or numbers in order. Combinations are the way of selecting the objects or numbers from a group of objects or collection, in such a way that the order of the objects does not matter.

Given,

The digits = 2,3,5,6,7 and 9

The number should be divisible by 5 and the digits cannot be repeated

When the unit digit of the number is either 5 or 0, then the number will be divisible by 5.

Number of possible ways to fill the unit place = 1

Number of possible ways to fill the tens place = 5

Number of possible ways to fill the hundredth place = 4

Number of three digit number can be formed =4×5×1=20

Hence, the number of 3 digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 which are divisible by 5 and none of the digits is repeated is 20

Learn more about permutation and combinations here

brainly.com/question/13387529

#SPJ4

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