Answer is: <span>percent ionization of aqueous acetic acid solution is 0.341%.
c(CH</span>₃COOH) = 1.55 M.
Ka(CH₃COOH) = 1.8·10⁻⁵.
Chemical reaction: CH₃COOH ⇄ CH₃COO⁻ + H⁺.
[CH₃COO⁻] = [H⁺] = x.
[CH₃COOH] = 1.55 M - x.
Ka = [CH₃COO⁻] · [H⁺] / [CH₃COOH].
1.8·10⁻⁵ = x² / (1.55 M - x).
Solve quadratic equation: x = 0.0053 M.
percent of ionization:
α = 0,0053 M ÷ 1.55 M · 100% = 0,341%
Answer:
a. 2500 ml of water is needed
Explanation:
V1C1=V2C2
(500)(5)=(1)V2
2500/1=V2
2500 = v2
55.5 I think but I may be wrong
Answer:
The formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Explanation:
Iron (ii) ions, Fe²⁺ have a positive charge of +2. Chromate ions, CrO₄²⁻, on the other hand have a positive charge of -2. When iron (ii) ions and chromate ions combine two form a compound, each ion will contribute a mole of ion towards the formation of the compound. This is in line with the idea that a compound carries no charge. The positive charge (+2) of the iron (ii) ions are balanced by the negative charge of the chromate ions as shown mathematically as follows;
+2 + (-2) = 0; i.e. Fe²⁺ + CrO₄²⁻ = FeCrO₄
Therefore, the formula of the compound formed by Iron (ii) ions and chromate ions is FeCrO₄
Given teh equation adn the heat of reaction, reaction 2's heat of reaction can be obtained by simply multiplying teh heat of reaction of 1 by 3. The final answer is -6129 kJ.
