(10.0 g Al2(SO3)3) / (294.1544 g Al2(SO3)3/mol) = 0.033996 mol Al2(SO3)3 (10.0 g NaOH) / (39.99715 g NaOH/mol) = 0.25002 mol NaOH
0.033996 mole of Al2(SO3)3 would react completely with 0.033996 x (6/1) = 0.203976 mole of NaOH, but there is more NaOH present than that, so NaOH is in excess and Al2(SO3)3 is the limiting reactant.
In order to find the amount of atoms you have to find the moles then multiply by Avogadro's Constant (L)
mol =
=
= 3.73 mol
Number of atoms of Cu = mol × L
= 3.73 mol × (6.02 × 10²³)
= 2.245 × 10²⁴ atoms of copper
Answer:
Velocity = Distance Covered÷Time Taken
Velocity = 4000÷8
V = 500
D. Chemical to thermal and electromagnetic