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uysha [10]
2 years ago
9

__________ disease is associated with the bilateral calcification of the amygdalas and surrounding areas of the anterior medial

lobes.
Biology
1 answer:
alex41 [277]2 years ago
6 0

Urbach Wiethe disease is associated with the bilateral calcification of the amygdala and surrounding areas of the anterior medial lobes.

Urbach Wiethe disease is an autosomal recessive genetic disorder. It causes bilateral degeneration of amygdala due to lipoid storage. The vocal cords are also thickened in this disease therefore resulting in a weakened voice.

Amygdala is an almond shaped structure present in the brain.  It is composed of gray matter, and is responsible for the expression of emotions. The major emotions displayed are fear, anger and pleasure. It is proved that is an organism lacks amygdala, it cannot express any emotions, even of fear.

To know more about amygdala, here

brainly.com/question/9888781

#SPJ4

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The most important function of nitrites in processed food is to a prevent browning. b inhibit germination of Clostridium botulin
tangare [24]

Answer:

B. inhibit the germination of Clostridium botulinum endospores.

Explanation:

Nitrite is used in meat curing, which is produced commercially as sodium nitriteand it is has been responsible for the preservation and characteristic color/ flavor of the cured meats. Cured meat products contain curing salts, usually salt (sodium chloride) and either nitrites or nitrates. The function of nitrite in processed meat is : (1) to stabilize the color of the lean tissues. Sodium nitrite, is most commonly used for curing (although in some products such as fermented ones, sodium nitrate is used too, because of the long aging period); pocessed meats like as bacon, ham, sausages etc.

These compounds help to prevent the growth of harmful bacteria. add a salty flavor. Clostridium botulinum produces heat-resistant endospores that are commonly that are able to survive under adverse conditions. Clostridium botulinum is commonly associated with bulging canned food; bulging, misshapen cans are due to an internal increase in pressure caused by gas produced by this bacteria.

3 0
4 years ago
Which of the following is most likely true of a protein that cotransports glucose and sodium ions into the intestinal cells of a
Step2247 [10]

Answer:

D) Transport of sodium ions down their electrochemical gradient facilitates the transport of glucose against its concentration gradient.

Explanation:

Active transport refers to the movement of molecules across biological membranes against a concentration gradient. Active transport can be divided into 1-primary active transport, which requires energy from the hydrolysis of adenosine triphosphate (ATP); and 2-secondary active transport, which requires an electrochemical gradient generated by pumping ions in/out of the cell. The case above described represent a type of secondary transport active because the movement of sodium (Na) ions is used as energy source to move glucose molecules against their concentration gradient.

3 0
3 years ago
Differences and simularities of Analog Transmisson and Digital Transmission?
lukranit [14]
The difference between analog and digital signals is that an analog signal is a continuous electrical message while digital is a series of values that represent information. Analog is conveyed by electrical current variations. Digital signals are relayed as a series of values that a device can read, such as a digital television. 
3 0
3 years ago
xxy Consider a pea plant- it has a gene controlling seed color- yellow Vs green; another gene controlling seed texture-smooth Vs
emmasim [6.3K]

Answer:

2 Smooth yellow : 1 smooth green : 1 wrinkled yellow : 0 wrinkled green

Explanation:

The cross between a true breeding smooth green and a true breeding wrinkled yellow produced a homogeneous smooth yellow F1 . According to Mendel's Law of Dominance, the traits that appeared in the progeny are dominant.

The parents were true breeding, so they are homozygous for all genes.

If the genes are linked, their genotypes can be written as:

     smooth green  X  wrinkled yellow

<h3>       Sy/Sy           X      sY/sY</h3><h3>F1:                    Sy/sY</h3><h3></h3>

The F1 is self-fertilized, so a cross Sy/sY x Sy/sY is done. If the genes are very tightly linked, almost no recombination happens between them and all gametes will be parental.

The F1 individuals can produce 2 types of gametes then: <em>Sy </em>and <em>sY</em>.

The expected offspring would be:

  • 1 Sy/Sy: Smooth green
  • 2 Sy/sY: Smooth yellow
  • 1 sY/sY: wrinkled yellow
3 0
3 years ago
In tomato plants, the germ cells are in the flowers. The yellow (Y) gene controls flower color, such that Y_ plants have yellow
LenKa [72]

***see attached pic***

You're given the phenotypes of the parents, with descriptions about their genotypes ("true breeding" = "homozygous" or "same alleles"), so it's helpful to start by writing out the genotypes of the parents.  Remember, there are two alleles for any given gene (you get one allele from each parent) and this problem is talking about 2 separate genes, so therefore our genotypes will have 2 genes x 2 alleles per gene = 4 alleles.

Once you've written the genotype, "FOIL" (first, outer, inner, last) the genotype to give you all the possible allele combinations that could be paired in that parent's gametes.

*These combinations^ will have one allele for each gene (example: YR) because the the offspring will inherit one allele for each gene from both parents when the parents' gametes come together (fertilization) for a total of two alleles for each gene.*

Your answer should be A.

3 0
3 years ago
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