Answer:
Original figure: (-6,-5)
final figure: (-6, 5)
Step-by-step explanation:
the point would fall at (-6, 5) because it is reflecting across the x-axis (the horizontal one) and since it is the original point is 5 away from the x-axis, the final point would be at 5 as well. the y-coordinate doesn't change because it is only reflecting over the x-axis. the shape would essentially be flipped if you reflected it over the x-axis, so the point would be on the bottom of the figure instead of the top. Hope this helps I tried my best to explain!
$x^2(x+1)+2(x+1)=(x^2+2)(x+1)$
Alan will be 50 yrs old and Aron will be 20 yrs old
Answer:
y = 6cos(π/2)t
Step-by-step explanation:
Given in the question that,
in a simple harmonic motion in which
at t=0 the amplitude is 6 cm, so the simple harmonic motion will be in cosine form. As in case of sine function, the value of function at t=0 is 0.
And,
the period is given as 4 sec
We know that model equation of simple harmonic motion is
<h3>y = a. cosb(t + c) + d</h3>
here,
a is amplitude
c is Horizontal shift or phase shift
d is Vertical shift
<h3>Step1</h3><h3>Find b</h3>
Period = 2 π / b
4 = 2π / b
b = 2π/4
b = 1π/2
<h3>Step2</h3><h3>Find shifts</h3>
Horizontal and vertical shifts are 0.
So, c = 0 and d = 0
<h3>Step3</h3><h3>Plug those values in the above in the equation</h3>
y = 6cos π/2 (t + 0) + 0
y = 6cos(π/2)t
Answer:
No solution
Step-by-step explanation:
5x + 12 + 3x = 8x - 5
8x + 12 = 8x - 5
12 ≠ - 5
No solution
