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snow_tiger [21]
2 years ago
5

IMMEDIATE HELP PLEASE

Mathematics
1 answer:
9966 [12]2 years ago
4 0

just deal with the power of the x , multiply and simplify

(  { {x}^{ \frac{3}{2} }})^{6}  =   {x}^{  {9} }

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A large washer has an outer radius of 10mm and a hole with a diameter of 14mm. What is the area of the washer? (Use π =3.14)
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Answer:

160.14  mm^2

Step-by-step explanation:

Area of a circle = pi r^2

subtract the area of the smaller circle from the larger

  note that the smaller radius = 7 mm

pi ( 10^2  - 7^2 ) =

3.14 ( 51) = 160.14 mm^2

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Start with -2 and you end with +7 what is the rule
nika2105 [10]
Add 9 because -2 to 7 equals 9 hope this helped


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Evaluate the following expression. 9+512/2​
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A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.
Kobotan [32]

Answer:

The numbers are

-2+3\sqrt{5}   and 3\sqrt{5}

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

so

x=y-2

y=x+2 ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

so

4y+x^2=49 ----> equation B

substitute equation A in equation B

4(x+2)+x^2=49

solve for x

x^2+4x-41=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

x^2+4x-41=0

so

a=1\\b=4\\c=-41

substitute in the formula

x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}

x=\frac{-4\pm\sqrt{180}} {2}

x=\frac{-4\pm6\sqrt{5}} {2}

x=-2\pm3\sqrt{5}

so

The positive real number is

x=-2+3\sqrt{5}

Find the value of y

y=x+2

y=-2+3\sqrt{5}+2

y=3\sqrt{5}

6 0
4 years ago
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