All values of x in the interval [0, 2pi] are x = π/6, 5π/6
<h3>How to find interval of trigonometric functions?</h3>
We are given the trigonometric function as;
14 sin2(x) = 7
Divide both sides by 7 by division property of equality to get;
sin2(x) = 7/14
sin2(x) = 0.5
2x = sin⁻¹0.5
x = 0.5sin⁻¹0.5
At the requested interval,
x = π/6, 5π/6
Thus, all values of x in the interval [0, 2pi] are x = π/6, 5π/6
Read more about Trigonometric intervals at; brainly.com/question/12502943
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