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1 year ago

A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form

Mathematics

1 answer:

daser333 [38]1 year ago

4 0

Step-by-step explanation:

as we have a point and the slope, we can start with the point-slope form and then transform.

the point-slope form is

y - y1 = a(x - x1)

(x1, y1) being a point on the line, a being the slope.

the slope-interceot form is

y = ax + b

a being the slope again, b being the y-intercept (the y value for x = 0).

so, we have

y - -5 = 5/2 × (x - -4)

y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10

y = 5x/2 + 5

y = (5/2)x + 5

and this is already the slope-intercept form. all done.

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$a_n=a_1+(n-1)r$

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