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1 year ago

A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form

Mathematics

1 answer:

daser333 [38]1 year ago

4 0

Step-by-step explanation:

as we have a point and the slope, we can start with the point-slope form and then transform.

the point-slope form is

y - y1 = a(x - x1)

(x1, y1) being a point on the line, a being the slope.

the slope-interceot form is

y = ax + b

a being the slope again, b being the y-intercept (the y value for x = 0).

so, we have

y - -5 = 5/2 × (x - -4)

y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10

y = 5x/2 + 5

y = (5/2)x + 5

and this is already the slope-intercept form. all done.

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A curve in polar coordinates is given by: r=9+3cosθ. Point P is at θ=21π/18 .?

ikadub [295]

Answer:

Step-by-step explanation:

Given that a curve in polar coordinates is given by:

r=9+3cosθ

a) At point P, we have

$θ=\frac{21\pi}{18}$

Substitute to get

$r=9+cos \frac{21\pi}{18}\\=9.3932$

b) Cartesian coordinate is

$x= rcos \theta=3.6934\\y =r sin \tjeta =8.6365$

c) At the origin r =0

when r =0

we have

$9+3cos\theta=0\\cos\theta =-3$

Since cos cannot take values as -3 it doe snot pass through origin.

6 0

2 years ago

1. -4x + 5 = 2x - 7 2. 6x - 8 = 4x + 2 3. -3x - 5 = 2x + 10

Svetllana [295]

Answer: 1. x=2

2. x=5

3.x=-3

Isolate the variable by dividing each side by factors that don't contain the variable.

Move all terms not containing x to the right side of the equation.

Hope this helped

7 0

2 years ago

PLEASE HELP ME THIS IS DUE TODAY AND I AM DEPRESSED ( uhm look at photo )

Anuta_ua [19.1K]

Answer:

C. 19

B. 47

C. 12

C. 10

C. -8

Step-by-step explanation:

for each equation you take the number given, input it as the value of the variable, and evaluate the equation

hopefully this helps :)

4 0

2 years ago

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

Answer:

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

Step-by-step explanation:

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

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2 years ago

Write a real world situation that could be represented by the system of equations shown below.

natali 33 [55]

You could say:

y = 4x + 10

John runs 10 miles a week, after every month he adds 4 miles.

y = 3x + 15

Mary runs 15 miles a week, after every month she adds 3 miles.

'y' would represent the total miles and 'x' would represent the number of months.

4 0

2 years ago