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dmitriy555 [2]
3 years ago
14

Solve the equation and check the solution. 14-2n=-32

Mathematics
1 answer:
makvit [3.9K]3 years ago
4 0

14 - 2n = -32

32 + 14 = 2n

46 = 2n

46/2 = n

23 = n


Checking:

14 - 2(23) = -32

14 - 46 = -32

-32 = -32 (Matched, answer is correct n = 23)

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1 yd = 36 inches....so 20 yds = 20*36 = 720 inches....+ 8 inches = 728 inches

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How many points should you give out per question?
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As much as you want ;)
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Let A be a set of numbers.
LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

a.

Let A be a set of all integers divisible by 5.

Let x,y∈A such that x=5m\,,\,y=5n

Find x+y,xy

x+y=5m+5n=5(m+n)

So, x+y is divisible by 5.

xy=(5m)(5n)=25mn=5(5mn)

So,

xy is divisible by 5.

Therefore, A is closed under addition and multiplication.

b.

Let  A = { 2n +1 | n ∈ Z}

Let x,y∈A such that x=2m+1\,,\,y=2n+1 where m, n ∈ Z.

Find x+y,xy

x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)

So,

x+y ∉ A

xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1

So,

xy∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

c.

Let A=\{2,5,8,11,14,...\}

Let x=2,y=5 but x+y=2+5=7∉A

Also,

xy=2(5)=10∉A

Therefore, A is not closed under addition and multiplication.

d.

Let A = { 17n: n∈Z}

Let x,y ∈ A such that x=17n,y=17m

Find x + y and xy

x+y=17n+17m=17(n+m)

xy=(17m)(17n)=289mn=17(17mn)

So,

x+y,xy ∈ A

Therefore, A is closed under addition and multiplication.

e.

Let A be the set of nonzero real numbers.

Let x,y ∈ A such that x=-1,y=1

Find x + y

x+y=-1+1=0

So,

x+y ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0
3 years ago
SImple geometry question.
expeople1 [14]

Answer:

Angle 1=135°

Angle 2=27°

Step-by-step explanation:

Okay, we know Angle JKL is 162°.

Angle JKL contains both Angle 1 and Angle 2.

So, we are able to deduce that:

Angle 1 + Angle 2=162°

We also know that Angle 1 is 5 times bigger than Angle 2.

Another way you could say this is:

Angle 1=5x

Angle 2=x

We have to figure out what x is first.

So, combine what we already know into a workable equation.

5x+x=162°

Combine like terms

6x=162°

Divide both sides by 6

162/6=27°

x=27°

Since Angle 2 is equal to x, that means Angle 2 is 27°

Meanwhile, to get Angle 1:

5(27)=135°

Angle 1=135°

Angle 2=27°

And, to check our work:

135+27=162

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I need help with this question i dont get it.
Vedmedyk [2.9K]

Answer:

y = -16

Step-by-step explanation:

First lets handle the fractional y's:

\frac{5}{2}y - \frac{1}{2}y = \frac{4}{2}y\\

This can be reduced down to 2y. That is easier to work with. Next we will rewrite the equation using or new value for y:

35 + 2y = 3

Subtract 35 from both sides:

2y = -32

Next, divide both sides by 2

y = -16

Check our answer:

35 + \frac{5}{2}(-16) - \frac{1}{2}(-16) = 3

35 -40 + 8 = 3

-5 + 8 = 3

3 = 3

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