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horrorfan [7]
4 years ago
11

What Went Wrong – Balancing Chemical Equations

Chemistry
1 answer:
OLEGan [10]4 years ago
4 0
1-It has to be 3 Fe and not Fe3.
2-The oxygens aren't balanced

Balanced equation:
3Fe+4H2O---->Fe3O4+4H2
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what is different between an ionic bond and and a covalent bond? a. an ionic bond shares electrons, and a covalent bond is an at
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I would pick either b) or D) but you just have to remember that not all ionicbonds will bond together, because some bonds are only negattive bonds, 
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4 years ago
Please help me I will give you the brain thing and extra points. image below part
jekas [21]
D is the correct answer... if u need in depth let me know
3 0
3 years ago
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If you add a solution of NaOH to a solution of H₂CO₃, two reactions occur, one after the other. Write the chemical equations for
Crazy boy [7]

We have a solution of NaOH and H₂CO₃

First, NaOH will dissociate into Na⁺ and OH⁻ ions

The Na⁺ ion will substitute one of the Hydrogen atoms on H₂CO₃ to form NaHCO₃

The H⁺ released from the substitution will bond with the OH⁻ ion to form a water molecule

If there were to be another NaOH molecule, a similar substitution will take place, substituting the second hydrogen from H₂CO₃ as well to form Na₂CO₃

6 0
3 years ago
1. Some athletes have as little as 3.0% body fat. If such a person has a body mass of 65 kg, how many pounds of body fat does th
77julia77 [94]
1. 3.0% ----> 3.0 kg fat= 100 kg body weigh
also remember that 1 kg= 2.20 lbs

65 kg  \frac{3.0 kg}{100 kg} x  \frac{2.20 lb}{1 kg} = 4.29 lbs

2. 0.94 g/mL----> 0.94 grams= 1 mL
1 Liters= 1000 mL
1kg= 1000 grams

3 Liters  \frac{1000 mL}{1 L} x   \frac{0.94 grams}{1 mL} x  \frac{1 kg}{1000 g} x   \frac{2.20 lbs}{1 kg}  = 6.20 lbs
3 0
3 years ago
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Calculate the molarity of a solution of sodium hydroxide, naoh, if 23.64 ml of this solution is needed to neutralize 0.5632 g of
GuDViN [60]
The  molarity  of  NaOH  needed  is  calculated   as  follows
calculate  the  moles  of  KhC8h4O4

that  is  moles  =  mass/molar  mass  of  KhC8h4O4(204.22 g/mol)

=0.5632g /204.22g/mol=  2.76  x10^-3  moles

write the  equation  for  reaction

khc8h4O4  +  NaOH  ---> KNaC8h4O4  +  H2O

from  the  equation  above  the   reacting  ratio   of   KhC8h4O4  to  NaOh  is  1:1  therefore  the  moles  of  Naoh  is  also  2.76  x10^-3  moles

molarity  of NaOh  =  (moles  of  NaOh /  volume ) x  1000

that  is { (2.76  x10^-3) / 23.64}  x100  =0.117 M
8 0
3 years ago
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