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Zolol [24]
3 years ago
6

What is the molality of an aqueous solution that contains 29.5 g of glucose (C6H12O6) dissolved in 950 g of water (H2O)?

Chemistry
1 answer:
Gnesinka [82]3 years ago
7 0
Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.

Molality = 29.5 g glucose (1 mol / 180.16 g ) / .950 kg water
Molality = 0.1724 mol / kg
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Mass of CuSO4● XH2O (g) = 1.6 grams BEFORE HEATING
Leokris [45]

0.06105 moles is the number of moles of water lost.

<h3>What is molar mass?</h3>

Molar mass is defined as the mass in grams of one mole of a substance.

Given data:

Mass of water = 1.1g

Molar mass water = 18.016 g/mol

Moles of water =?

These quantities are related by the following equation;

Moles = \frac{Mass}{Molar \;mass}

Substituting the values of the quantities and solving for moles, we have;

Moles =  \frac{1.1 }{18.016} = 0.06105 moles.

Hence, the 0.06105 moles is the number of moles of water lost.

Learn more about molar mass here:

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7 0
2 years ago
True or False?
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4 0
2 years ago
What is the percent composition of phosphoric acid H3PO4
Agata [3.3K]
Hey there!:

Molar mass H3PO4 = <span>97.9952 g/mol

Atomic Masses :

H = </span><span>1.00794 a.m.u

</span>P = <span>30.973762 a.m.u

</span>O =  15.9994 a.m.u<span>

H % =  [ ( 1.00794 * 3 ) / </span> 97.9952  ]  * 100

H% = <span>3.0857 %

P % = [ ( </span>30.973762 * 1 ) / 97.9952 ] * 100

P% = <span>31.6074 %

O % = [ ( </span>15.9994 * 4 ) / 97.9952 ] * 100

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5 0
3 years ago
I need help solving this!
zmey [24]

Answer: Moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

Explanation:

Given: Mass of methane = 146.6 g

As moles is the mass of a substance divided by its molar mass. So, moles of methane (molar mass = 16.04 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{146.6 g}{16.04 g/mol}\\= 9.14 mol

The given reaction equation is as follows.

C + 2H_{2} \rightarrow CH_{4}

This shows that 2 moles of hydrogen gives 1 mole of methane. Hence, moles of hydrogen required to form 9.14 moles of methane is as follows.

Moles of H_{2} = \frac{9.14}{2}\\= 4.57 mol

Thus, we can conclude that moles of hydrogen required are 4.57 moles to make 146.6 grams of methane, CH_{4}.

5 0
3 years ago
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