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3 years ago

What is the molality of an aqueous solution that contains 29.5 g of glucose (C6H12O6) dissolved in 950 g of water (H2O)?

1 answer:

7 0

Molality is one way of expressing concentration of a solute in a solution. It is expressed as the mole of solute per kilogram of the solvent. To calculate for the molality of the given solution, we need to convert the mass of solute into moles and divide it to the mass of the solvent.

Molality = 29.5 g glucose (1 mol / 180.16 g ) / .950 kg water
Molality = 0.1724 mol / kg

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Answer:

nitrogen i think but not sure

Explanation:

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Radio waves travel at the speed of light which is 3.00 x 10^8. How many minutes does it take for a radio message to reach saturn

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Answer:

43.89 min

Explanation:

Given that:-

The speed of light = $3.00\times 10^8\ m/s$

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So,

Distance = $7.9\times 10^8\times 1000\ m=7.9\times 10^{11}\ m$

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$Speed=\frac{Distance}{Time}$

Thus,

$3.00\times 10^8=\frac{7.9\times 10^{11}}{Time}$

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Time= $\frac{2633.33}{60}\ min=43.89\ min$

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3 years ago

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A sample of nitrogen gas had a volume of 500. ml, a pressure in its closed container of 740 torr and a temperature 25 degrees c

Semenov [28]

Question:
<span>A sample of nitrogen gas had a volume of 500mL, a pressure in its closed container of 740 torr and a temperature of 25°c. what was the volume of gas when the temperature was changed to 50°c and the new pressure was 760 torr?

Answer:

Data Given:
V</span>₁ = 500 mL

P₁ = 740 torr

T₁ = 25 °C + 273 = 298 K

V₂ = ?

P₂ = 760 torr

T₂ = 50 °C + 273 = 323 K

Solution:
Let suppose the gas is acting Ideally, then According to Ideal Gas Equation,

P₁ V₁ / T₁ = P₂ V₂ / T₂

Solving for V₂,

V₂ = (P₁ V₁ T₂) ÷ (T₁ P₂)

Putting Values,

V₂ = (740 torr × 500 mL × 323 K) ÷ (298 K × 760 torr)

V₂ = 527.68 mL

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3 years ago