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Eduardwww [97]
2 years ago
5

. y = x2 + 3 y = x + 5

Mathematics
1 answer:
ddd [48]2 years ago
7 0
I assume you mean x squared in the first equation

Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0

Then factorise it to (x-2)(x+1) = 0
And solve both parts separately

x + 1 = 0
x = -1

x-2 = 0
x = 2

Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
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Which integer is greater than -79 but less than -74?<br> A) -76 B) -80 C) -79 D) 0
IgorC [24]
My best choice is A. -76. I might be wrong! Best of luck. :-)
5 0
3 years ago
Read 2 more answers
In health class, students record the weights of the sandwiches they have for lunch. The weights are shown in the line plot below
Dvinal [7]
To find the average weight, you need to add all of the numbers and then divide them
I'll start off by doing this:
1/8+1/8 = 2/8
1/4+1/4+1/4+1/4 = 1
3/8+3/8 = 6/8
1/2+1/2 = 1
then I'll add them together:
2/8+6/8 = 1
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now we need to divide the amount of numbers. the amount of sandwiches weighted (10) will have to be divided
therefore, we get 3/10. because this can't be simplified, this will be your final answer.
4 0
3 years ago
Solve 81^x = 27^^^x + 2.<br><br> A. x = 1<br> B. x = 2<br> C. x = 5<br> D. x = 6
omeli [17]

Answer:

x=6

Step-by-step explanation:

81^x=27^(x+2)

3^4x=3^3(x+2)

4x=3(x+2)

4x=3x+6

x=6

6 0
3 years ago
Read 2 more answers
Pls look at the picture
-Dominant- [34]

9514 1404 393

Answer:

  see below

Step-by-step explanation:

The area of a square is the square of the side length, as shown in the given table.

The area of a circle is pi (π) times the square of the radius. For a radius that is the same as the side length of a square, the circle will have an area π times as large.

For an input of 3, the square area function outputs 9.

For an input of 3, the circle area function outputs 9π, about 28.3.

3 0
3 years ago
How many 7-digit phone numbers are possible, assuming that the first digit can’t be a 0 or a 1? (b) re-solve (a), except now ass
sladkih [1.3K]
A. We are going to form 7 digit numbers from the set {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}

where the first digit cannot be 0 or 1.

so we have 8 choices for the 1. digit, and 10 choices for all the other 6 digits.

this means there are 8*10*10*10*10*10*10=8* 10^{6} possible numbers.

b.

consider the numbers which start with 911. There are 10*10*10*10=10 ^{4} such numbers, since for the 4th, 5th, 6th and 7th digits we have 10 choices.

then we remove this number, from the one we found in a:

There are in total 8* 10^{6}-10^{4}=7,990,000 numbers which don't start with 911.


Answer:

a.8*10^{6}
b.7,990,000

3 0
3 years ago
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