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Leona [35]
3 years ago
10

1.) A.) tan 50° B.) cot 50° C.) sin 50° D.) cos 50° E.) cot 50°

Mathematics
2 answers:
Elina [12.6K]3 years ago
5 0

Answer:

cot 50 is thr answer

Step-by-step explanation:

Elan Coil [88]3 years ago
4 0

Answer:

\cot 50 \textdegree

Step-by-step explanation:

\cos\theta=\frac{Adjacent}{Hypotenuse}\\ \\\sin\theta=\frac{Opposite}{hypotenuse}\\ \\\tan\theta=\frac{Opposite}{Adjacent}\\ \\\cot\theta=\frac{Adjacent}{Opposite}\\ \\\frac{\cos\theta}{\sin\theta}=\frac{\left(\frac{Adjacent}{Hypotenuse}\right)}{\left(\frac{Opposite}{Hypotenuse}\right)}=\frac{Adjacent}{Opposite}=\cot\theta\\ \\\Rightarrow \frac{\cos\theta}{\sin\theta}=\cot\theta\\ \\Substitute \ \theta=50\textdegree\\ \\\frac{\cos50\textdegree}{\sin50\textdegree}=\cot50\textdegree

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Answer:

x = \frac{mn(q-p)}{n-m}

Step-by-step explanation:

collect the fractional terms on the left side of the equation and other terms on the right side

subtract \frac{x-n}{n} from both sides

\frac{x-m}{m} - \frac{x-n}{n} + p = q

subtract p from both sides

\frac{x-m}{m} - \frac{x-n}{n} = q - p

We require the fractions to have a common denominator of mn

multiply the numerator/denominator of the first fraction by n and the numerator/denominator of the second fraction by m

\frac{n(x-m)}{mn} - \frac{m(x-n)}{mn} = q - p

distribute and simplify the numerators of the fractions

\frac{nx-nm-mx+mn}{mn} = q - p

\frac{nx-mx}{mn} = q - p

factor out x from each term on the numerator

\frac{x(n-m)}{mn} = q - p

multiply both sides by mn

x(n - m) = mn(q - p)

divide both sides by (n - m)

x = \frac{mn(q-p)}{n-m} → n ≠ m






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