Question

The height of a triangle is 4 in. greater than twice its base. The area of the triangle is no more than 168 in.2. Which inequality can be used to find the possible lengths, x, of the base of the triangle? mc015-1.jpg mc015-2.jpg mc015-3.jpg mc015-4.jpg

Answer 1

Answer:

b

Step-by-step explanation:

got it on edge

Answer 2

Let

x-------> the length of the base of triangle

y-------> the height of the triangle

we know that

the area of the triangle is equal to

$A=\frac{1}{2}xy$

in this problem we have

$A \leq 168\ in^{2}$

so

$\frac{1}{2}xy\leq 168$ --------> equation $1$

$y=2x+4$ --------> equation $2$

Substitute equation $2$ in equation $1$

$\frac{1}{2}x[2x+4]\leq 168$

$x^{2}+2x \leq 168$

therefore

the answer is

The inequality that can be used to find the possible lengths, x, of the base of the triangle is  $\frac{1}{2}x[2x+4]\leq 168$ or $x^{2}+2x \leq 168$