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Temka [501]
3 years ago
7

From the beginning of the day the temperature rose 15° so that by 4 pm it was 87°. What was the temperature at the start of the

day?
Mathematics
1 answer:
myrzilka [38]3 years ago
5 0

If it rose to 15 you should do 87+15 because it was higher

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Mariana [72]

Thislink has the answer: brainly.com/question/19701013?answering=true&answeringSource=greatJob%2FquestionPage%2F3

5 0
3 years ago
Which theorem proves that the triangles are congruent?
ddd [48]
Hello!

Looking at the image above, we are given that side BE is congruent to side ED while side AE is congruent to side EC. This can be written as follows:

BE = ED
AE = EC

In this case, ∠1 and ∠2 can be classified as vertical angles. Vertical angles are the two angles on opposite sides of two intersecting lines. These angles are always congruent to one another. Consequently, ∠1 and ∠2 must also be congruent to one another. This can be written as follows:

∠1 = ∠2

We have now proven the congruency of two sides and one angle. Because the angle lies between the two sides, this implies the use of SAS (side-angle-side).

Therfore, the correct answer is B.

I hope this helps!

6 0
3 years ago
Read 2 more answers
Solve n^4-11n^2+30÷n^4-7n^2+10
Morgarella [4.7K]
Factor the numerator and denominator...

(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)

[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]

[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)]  notice the (n^2-5)s cancel out

(n^2-6)/(n^2-2)  

We could further factor this because each is a difference of squares to:

[(n+√6)(n-√6)]/[(n+√2)(n-√2)
8 0
3 years ago
Find the equation of a line, in slope intercept form of a line that passes through the point (9,2) and is perpendicular to the l
son4ous [18]

Answer:

the first one  is correct ive T a k e n this testing.

Step-by-step explanation:

7 0
3 years ago
Find the
Vlad [161]

Answer:

Ending Balance = 600 * (1.05)^6

Ending Balance = 600 * 1.3400956406

Ending Balance = 804.06

Step-by-step explanation:

4 0
4 years ago
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