Ask question

Ask question

All categories

2 years ago

7

From the beginning of the day the temperature rose 15° so that by 4 pm it was 87°. What was the temperature at the start of the

day?

1 answer:

myrzilka [38]2 years ago

5 0

If it rose to 15 you should do 87+15 because it was higher

You might be interested in

The parabola y =x^2 is scaled vertically by a factor of 5/2

NNADVOKAT [17]

to graph f (x) + k, move the graph k units up..your answer should be;

y = x ^ 2 + 5/2

7 0

2 years ago

Read 2 more answers

What is the simplified version of 3\sqrt{135}

Aleonysh [2.5K]

Answer:

The simplified version of $\sqrt[3]{135}$ is $3\sqrt[3]{5}$ .

Step-by-step explanation:

The given expression is

$\sqrt[3]{135}$

According to the property of radical expression.

$\sqrt[n]{x}=(x)^{\frac{1}{n}}$

Using this property we get

$\sqrt[3]{135}=(135)^{\frac{1}{3}}$

$\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}$

$\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}$

$\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}$ $[\because (ab)^x=a^xb^x]$

$\sqrt[3]{135}=3\times \sqrt[3]{5}$ $[\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]$

$\sqrt[3]{135}=3\sqrt[3]{5}$

Therefore the simplified version of $\sqrt[3]{135}$ is $3\sqrt[3]{5}$ .

7 0

3 years ago

Read 2 more answers

Factor completely 5x^2 + 20x

murzikaleks [220]

Answer: 5x(x + 4)

hope i helped

7 0

2 years ago

Read 2 more answers

1.What is the equation of the line perpendicular to that passes through ? Write your answer in slope-intercept form. Show your

Juliette [100K]

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. $y=\frac{1}{3}x + 2$

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=1$ . We write

$(y-1)=m(x--3)\\(y-1)=m(x+3)$

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

$(y-1)=\frac{1}{3}(x+3)$

Simplify for slope intercept form.

$(y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2$

3 0

3 years ago

Social studies Geometry P.11 Similarity and altitudes in right triangles CEZ You have priz If SU = 28 and UV = 6, what is TU? T

Alex777 [14]

Answer:

TU ≈ 12.96

Step-by-step explanation:

Using the Altitude on Hypotenuse theorem

(leg of outer triangle)² = (part of hypotenuse below it) × (whole hypotenuse)

TU² = UV × SU = 6 × 28 = 168 ( take square root of both sides )

TU = $\sqrt{168}$ ≈ 12.96 ( to the nearest hundredth )

7 0

2 years ago