Step-by-step explanation:
Use the method of TOA CAH SOH.
![tan(51.3) = \frac{opp}{adj} \\ \tan(51.3) = \frac{u}{4} \\ u = 4 \tan(51.3)](https://tex.z-dn.net/?f=tan%2851.3%29%20%3D%20%20%5Cfrac%7Bopp%7D%7Badj%7D%20%20%5C%5C%20%20%5Ctan%2851.3%29%20%20%3D%20%20%5Cfrac%7Bu%7D%7B4%7D%20%20%5C%5C%20u%20%3D%204%20%5Ctan%2851.3%29%20)
![cos(51.3) = \frac{adj}{hypo} \\ \cos(51.3) = \frac{4}{v} \\ v \cos(51.3) = 4 \\ v = \frac{4}{ \cos(51.3) }](https://tex.z-dn.net/?f=%20cos%2851.3%29%20%20%3D%20%20%5Cfrac%7Badj%7D%7Bhypo%7D%20%20%5C%5C%20%20%5Ccos%2851.3%29%20%20%3D%20%20%5Cfrac%7B4%7D%7Bv%7D%20%20%5C%5C%20v%20%5Ccos%2851.3%29%20%20%3D%204%20%5C%5C%20v%20%3D%20%20%5Cfrac%7B4%7D%7B%20%5Ccos%2851.3%29%20%7D%20)
Perimeter of triangle = Sum of all sides =
![u \: + \: v + 4](https://tex.z-dn.net/?f=u%20%5C%3A%20%20%2B%20%20%5C%3A%20v%20%2B%204)
Answer:
7/25
Step-by-step explanation:
θ lies in quadrant ii
so 2θ lies in quadrant iv
csc θ=5/3
sin θ=3/5 (sin θ=1/csc θ)
[cos(α+β)=cosαcosβ-sinαsinβ]
cos (2θ)=cos(θ+θ)=cos θ cos θ-sin θ sin θ=cos² θ-sin ²θ=1-sin²θ-sin²θ=1-2sin²θ
=1-2 (3/5)²
=1-2(9/25)
=1-18/25
=(25-18)/25
=7/25
Step-by-step explanation:
I hope you have a good day
Answer:
f(2) = 16
or
y = 16
Step-by-step explanation:
Step 1: Write out function
y = 6x + 4
Step 2: Define variable for problem
<em>x</em> = 2
Step 3: Plug into function f(x)
f(2) = 6(2) + 4
f(2) = 12 + 4
f(2) = 16
Step 4: Change f(2) to y
y = 16